Answer:
Explanation:
We will use the equation F - f = ma, which is a fancy way of stating Newton's 2nd Law.
F = +50.0,
f = -30.0,
m = 7.60 kg. Therefore:
50.0 - 30.0 = 7.60a and
20.0 = 7.60a and
a = 20.0/7.60 so
a = 2.63 m/s/s to the right
Answer:
Explanation:
To get the person Moving you have to overcome the static (means not moving) friction coefficient. U(static)
To get the person going at the same speed you have to overcome the kinetic friction coefficient. U(Kinetic)
Force to get him moving is 198 N. Force = ma = U(static)Mg
combining the 2 equations you get 198N = U(static)* 55kg *9.8m/s^2 Solve for U(static)
Same equation to keep him moving except with the dynamic force and the dynamic U
175N= U(kinetic)*55kg*9.8m/s^2 Solve (U dynamic)
We need more evidence to be provided
Odpowiedź:
0,049 m / s
Wyjaśnienie:
Biorąc pod uwagę, że:
Dystans biegu = 900m
Czas trwania = 205 minut
Długość przejścia = 300 m
Zajęty czas = 205 minut
Średnia prędkość :
(Przebieg + pokonany dystans) / całkowity czas
Średnia prędkość :
(900 m +. 300 m) / 205 + 205
1200 m / 410 minut
Minuty do sekund
1200 / (410 * 60)
1200/24600
= 0,0487804
= 0,049 m / s
Answer
given,
mass of satellite = 545 Kg
R = 6.4 x 10⁶ m
H = 2 x 6.4 x 10⁶ m
Mass of earth = 5.972 x 10²⁴ Kg
height above earth is equal to earth's mean radius
a) satellite's orbital velocity
centripetal force acting on satellite = 
gravitational force = 
equating both the above equation
v = 5578.5 m/s
b) 
T = 14416.92 s
T = 4 hr
c) gravitational force acting
F = 5202 N
