Answer:
total amount of fluoride 3.6 *10^6 g
Explanation:
we know that
volume of reservoir
=
= 2.25*10^6 m^3
denso=ity of water = 1000 kg/m3
mass of water = 1000*2.25*10^6
= 2.25*10^9 kg = 2.25*10^12 g
fluoride 1.6 ppm
total amount of fluoride
= 3.6 *10^6 g
Answer:
velocity during second d = 20.0 mi/h
Explanation:
Total distance travelled is 2d, with an average velocity of 30.0 mi/h you can express the time travelled in terms of d:
distance = velocity * time
time = distance / velocity
time = 2d/30.0
The time needed for the first d at 60.0 is:
time = d/60.0
The time in the second d you can get it by substracting both times (total time - time for the first d)
second d time = 2d/30.0 - d/60.0
= 4d/60.0 - d/60.0
= 3d/60.0
and with the time (3d/60.0) and the distance travelled (d) you can get the velocity:
velocity = distance / time
velocity = d / (3d/60.0)
= 60.0/3 = 20.0 mi/h
Answer:
a cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speed
Answer:
0.08 ft/min
Explanation:
To get the speed at witch the water raising at a given point we need to know the area it needs to fill at that point in the trough (the longitudinal section), which is given by the height at that point.
So we need to get the lenght of the sides for a height of 1 foot. Given the geometry of the trough, one side is the depth <em>d</em> and the other (lets call it <em>l</em>) is given by:
since the difference between the upper and lower base is the increase in the base and we are only at halft the height.
Now we can calculate the longitudinal section <em>A</em> at that point:
And the raising speed <em>v </em>of the water is given by:
where <em>q</em> is the water flow (1 cubic foot per minute).