Answer:
The coefficient of kinetic friction is 0.51.
Explanation:
Given that,
Applied force, F = 75 N
Mass of a box, m = 15 kg
The acceleration of the box is 3 m/s²
We need to find the coefficient of kinetic friction. It is given by the formula as follows :

Where,
, is the normal force

So, the coefficient of kinetic friction is 0.51.
the velocity would be 0 mph
The answer is B.
Answer:
Average speed: 86 km/h
Explanation:
Driving from San Antonio to Houston:
1st. half time: 54km/h
2nd. half time: 118 km/h
Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h} }{2}=86 \frac{km}{h} [\tex]
Driving way back:
1st. half time: 54km/h
2nd. half time: 118 km/h
Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h} }{2}=86 \frac{km}{h} [\tex]
As in both routes we have the same average speed, then the average speed for the whole trip is 86 km/h
Answer
given,
mass of jogger = 67 kg
speed in east direction = 2.3 m/s
mass of jogger 2 = 70 Kg
speed = 1.3 m/s in 61 ° north of east.
jogger one

now
P = P₁ + P₂
magnitude




the angle is
north of east