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Elanso [62]
3 years ago
7

Suppose an object’s initial velocity is 10 m/s and its final velocity is 4 m/s. Mass is constant.

Physics
1 answer:
galina1969 [7]3 years ago
8 0

The negative work done states that the work is done by the object and not on the object.

<u>Explanation: </u>

According to work energy theorem, the work done is equal to change in kinetic energy exhibited by the body. As the mass of the object is constant, and the velocity is decreased from 10 m/s to 4 m/s, the work done will be

           W=\frac{1}{2} \times\left(u^{2}-v^{2}\right)

Here W is the work done, m is the mass and v is the final and u is the initial velocity of the object. As the initial velocity is greater than the final velocity. So

          W=\frac{1}{2} \times\left(4^{2}-10^{2}\right)=\frac{1}{2} \times(16-100)=\frac{1}{2} \times(-84)= - 42 J

So the work done is negative for the given situation. The negative work done states that the work is done by the object and not on the object.

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Answer:

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Explanation:

a) For this part we use the concept of density

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As we are told that 1 carat is 0.2g we can make a rule of proportions (three) to find the weight of 2.8 carats

    m = 2.8 Qt (0.2 g / 1 Qt) = 0.56 g = 0.56 10-3 kg

   

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    V = 0.56 / 3.52

    V = 0.159 cm3

We use the relation of the bulk module

    B = P / (Δv/V)

    ΔV = V P / B

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b) indicates that we approximate the diamond to a sphere

    V = 4/3 π R³

For this part let's look for the initial radius

    R₀ = ∛ ¾ V /π

    R₀ = ∛ (¾ 0.159 /π)

    R₀ = 0.3361 cm

Now we look for the final volume and with this the final radius

    V_{f} = V + ΔV

    V_{f} = 0.159 + 2.118 10⁻²

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The radius increment is

    ΔR = R_{f} - R₀

    ΔR = 0.3504 - 0.3361

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Explanation:

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