Answer:
ω=6684.51 rpm
Explanation:
r= 30cm= 0.3m
a= 15000gs (convert to m/s^{2}
1g = 9.8 m/s^{2}
a= 15000 *9.8 = 147000 m/s^{2}
a=\frac{v^{2} }{r}
147000 = \frac{v^{2} }{0.3}
147000*0.3 = v^{2}
44100 = v^{2}
√44100 = v
210m/s = v
v=210m/s (linear velocity)
we will convert this to angular velocity
ω=\frac{v}{r}
ω= 210/0.3
ω= 700 rads^{-1}
we will convert this to rev per minute
1rad per second = 9.5493 rev per minute
ω= 700*9.5493
ω=6684.51 rpm
Answer:
1.3.
Explanation:
From the question given above, the following data were obtained:
Sine of incident angle (Sine i) = 0.217
Sine of refracted angle (Sine r) = 0.173
Refractive index (n) =?
From snell's law, the Refractive index is simply defined as the ratio of the sine of the incident angle to sine of the refracted angle. Mathematically, it is expressed as:
Refractive index = Sine of incident angle / sine of refracted angle
n = Sine i / Sine r
With the above formula, we can obtain index of refraction as shown below:
Sine of incident angle (Sine i) = 0.217
Sine of refracted angle (Sine r) = 0.173
Refractive index (n) =?
n = Sine i / Sine r
n = 0.217 / 0.173
n = 1.3
Thus, the index of refraction is 1.3.
Two or three i believe to be the answer
Explanation:
heat engine is correct answer
