Answer:
Explanation:
Usually office's networks works using the TCP/IP protocol, this mean that each workstation has an assigned IP. This IP are the directions gave to each computer on the network,
This IP are usually asigned by a DHCP Server. Servers every time a new device connect to the Network, assigns to it an IP, this way every Computer will know how to send or request information from that Computer.
In the TCP/IP protocol is not posibble for two computer to have the same IP. This causes what it call IP Conflict, IP Conflict make imposible the comunications between those devices and the Network.
On Power outages all the Computer are turn off, because of this they disconnect from the Network and need to requests IP one more time to gain comunication,
We this in mind, we can predict that frequent power outages can cause for all the Computer in the Network to request new IPs very frequently this will cause IP Conflict in several units, disconnecting them from the network and making them no longer able to find files on the network. To fix this, what can be done it to establish Static IP to every workstation, this way we they request a new IP, the DHCP Serve will assign them the same IP form every session.
This way, the IP Conficlt can end. Another option is to make the DHCP to assign new IP to every unit one more time, eliminating the machines with same IP.
The density of the substance is<u> 10.5 g/cm³.</u>
The jewelry is made out of <u>Silver.</u>
Density ρ is defined as the ratio of mass <em>m</em> of the substance to its volume V<em>. </em> The cylinder contains a volume <em>V₁ of water</em> and when the jewelry is immersed in it, the total volume of water and the jewelry is found to be V₂.
The volume <em>V</em> of the jewelry is given by,
![V=V_2 -V_1](https://tex.z-dn.net/?f=%20V%3DV_2%20-V_1%20)
Substitute 48.6 ml for <em>V₁ </em>and 61.2 ml for V₂.
![V=V_2 -V_1\\ =61.2 ml -48.6 ml\\ =12.6 ml](https://tex.z-dn.net/?f=%20V%3DV_2%20-V_1%5C%5C%20%3D61.2%20ml%20-48.6%20ml%5C%5C%20%3D12.6%20ml%20)
calculate the density ρ of the jewelry using the expression,
![\rho =\frac{m}{V}](https://tex.z-dn.net/?f=%20%5Crho%20%3D%5Cfrac%7Bm%7D%7BV%7D%20%20)
Substitute 132.6 g for <em>m</em> and 12.6 ml for <em>V</em>.
![\rho =\frac{m}{V}\\ =\frac{132.6 g}{12.6 ml} \\ =10.5 g/ml](https://tex.z-dn.net/?f=%20%5Crho%20%3D%5Cfrac%7Bm%7D%7BV%7D%5C%5C%20%3D%5Cfrac%7B132.6%20g%7D%7B12.6%20ml%7D%20%5C%5C%20%3D10.5%20g%2Fml%20)
Since
,
The density of the jewelry is <u> 10.5 g/cm³.</u>
From standard tables, it can be seen that the substance used to make the jewelry is <u>silver</u><em><u>, </u></em>which has a density 10.5 g/cm³.
Answer:
what should be done io protect forests
Answer:
x=22.33m
Explanation:
Kinematics equation for constant deceleration:
![x =v_{o}*t - 1/2*at^{2}=8.9*6.3-1/2*1.70*6.3^{2}=22.33m](https://tex.z-dn.net/?f=x%20%3Dv_%7Bo%7D%2At%20-%201%2F2%2Aat%5E%7B2%7D%3D8.9%2A6.3-1%2F2%2A1.70%2A6.3%5E%7B2%7D%3D22.33m)
Answer:
The period of oscillation is 1.33 sec.
Explanation:
Given that,
Mass = 275.0 g
Suppose value of spring constant is 6.2 N/m.
We need to calculate the angular frequency
Using formula of angular frequency
![\omega=\sqrt{\dfrac{k}{m}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D)
Where, m = mass
k = spring constant
Put the value into the formula
![\omega=\sqrt{\dfrac{6.2}{275.0\times10^{-3}}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7B6.2%7D%7B275.0%5Ctimes10%5E%7B-3%7D%7D%7D)
![\omega=4.74\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D4.74%5C%20rad%2Fs)
We need to calculate the period of oscillation,
Using formula of time period
![T=\dfrac{2\pi}{\omega}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2%5Cpi%7D%7B%5Comega%7D)
Put the value into the formula
![T=\dfrac{2\pi}{4.74}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2%5Cpi%7D%7B4.74%7D)
![T=1.33\ sec](https://tex.z-dn.net/?f=T%3D1.33%5C%20sec)
Hence, The period of oscillation is 1.33 sec.