Ask question

Ask question

All categories

3 years ago

10

A body of mass 1.0 kg initially at rest slides down an incline plane that is 1.0 m high and 10.0 m long. If the body experiences

a constant resistive force of 0.5 N over the slope, what is the KE of the body at the base of the plane?

1 answer:

Ksivusya [100]3 years ago

6 0

Answer:

answer is

Explanation:

because

You might be interested in

What is the wavelength of a wave that has a speed of 26 m/s and a frequency of 49? ? Show your work

nirvana33 [79]

Answer:

Wave speed = Wavelength x Frequency

26 m/s = Wavelength x 49

Divide by 49 to find the wavelength:

The wavelength is approximately 0.53

Let me know if this helps!

6 0

3 years ago

The first electric generators used direct current, so they needed to be reversed manually on a regular basis in order to work pr

djyliett [7]

Could I see the questions

4 0

3 years ago

Never mind i dont need help anymore

Usimov [2.4K]

Yay good for you!!!!

8 0

3 years ago

As an intern at an engineering firm, you are asked to measure the moment of inertia of a large wheel for rotation about an axis

klio [65]

Hi there!

We can begin by finding the acceleration of the block.

Use the kinematic equation:

$d = v_0t + \frac{1}{2}at^2$

The block starts from rest, so:

$d = \frac{1}{2}at^2\\\\12 = \frac{1}{2}a(4^2)\\\\\frac{24}{16} = a = 1.5 m/s^2$

Now, we can do a summation of forces of the block using Newton's Second Law:

$F = ma = m_bg - T$

mb = mass of the block

T = tension of string

Solve for tension:

$T = m_bg - ma = 8.2(9.8) - 8.2(1.5) = 68.06 N$

Now, we can do a summation of torques for the wheel:

$\Sigma \tau = rF\\\\\Sigma\tau = rT$

Rewrite:

$I\alpha = rT$

We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:

$\alpha = a/r\\\\\alpha = 1.5/.42= 3.57 rad/sec^2$

Now, plug in the values into the equation:

$I(3.57) = (0.42)(68.06)\\\\I = (0.42)(68.06)/(3.57) = \boxed{8.00 kgm^2}$

8 0

2 years ago

C-14 is an isotope of the element carbon. How does it differ from the carbon atom seen here? A) C-14 has two more protons. B) C-

mylen [45]

Answer:

C-14 has two more neutrons.

Explanation:

4 0

3 years ago

Read 2 more answers