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Elenna [48]
1 year ago
13

What are levers used for? (science)

Chemistry
1 answer:
Assoli18 [71]1 year ago
8 0

According to the research, levers are used to modify or generate a force and transmit displacement.

<h3>What are levers?</h3>

It is a simple machine composed of a rigid bar of some moderately resistant material, which rotates freely on a support point.

It can be used to maximize the mechanical force applied to an object, increasing its speed or the distance it travels, by applying a proportionally smaller amount of force.

Therefore, we can conclude that according to the research, levers are used to modify or generate a force and transmit displacement.

Learn more about levers here: brainly.com/question/19732425

#SPJ1

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Write any five prevention of cancer ​
natulia [17]

Answer:

Don't use tobacco or tobacco-containing products

Maintain a healthy diet

Protect yourself from the sun, make sure to use sunscreen

Go to the doctor regularly, for general checkups

Stay physically active

Explanation:

hope this helps :)

8 0
2 years ago
Label the particles, charges, &amp; mass for Elements: 6, 8 &amp; 10?
pashok25 [27]

Answer:

charges, & mass

Explanation:

3 0
2 years ago
4. Given the balanced equation: 2Na + S → Na₂S
PtichkaEL [24]

Answer:

Option D. 30 g

Explanation:

The balanced equation for the reaction is given below:

2Na + S —> Na₂S

Next, we shall determine the masses of Na and S that reacted from the balanced equation. This is can be obtained as:

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of S = 32 g/mol

Mass of S from the balanced equation = 1 × 32 = 32 g

SUMMARY:

From the balanced equation above,

46 g of Na reacted with 32 g of S.

Finally, we shall determine the mass sulphur, S needed to react with 43 g of sodium, Na. This can be obtained as follow:

From the balanced equation above,

46 g of Na reacted with 32 g of S.

Therefore, 43 g of Na will react with = (43 × 32)/46 = 30 g of S.

Thus, 30 g of S is needed for the reaction.

8 0
2 years ago
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
2 years ago
NaCl+AgC2H3O2--&gt; NaC2H3O2+AgCl <br><br><br> what is this balanced
Westkost [7]

Answer:

It is already balanced equation

3 0
2 years ago
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