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nlexa [21]
3 years ago
5

I need help with my chemistry but you can oonly choose one option​

Chemistry
2 answers:
GrogVix [38]3 years ago
7 0

2NaCl-->2Na+ Cl2

Correct Option- Decomposition

_____________________________

Decomposition reactions are those reactions in which a compound breaks or splits into two or more simpler substances. In such reactions, one reactant breaks down to form many i.e. at least two products. These reactions require energy to break existing bonds, so they take place in the presence of heat, light, or electricity.

Example:- AB--> A+B

<h3>Hope This Helps You ❤️</h3>
Anettt [7]3 years ago
3 0

Answer:

well it is an Synthesis reaction

Explanation:

  • in the view of the fact that a sodium metal .."Sodium" reacts with an "chloride gas" to form a sodium Chloride. NaCL
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Which molecule is polar, based on structure? 1) sulfur dioxide 2) carbon disulphide 3) ethylene 4) carbon tetrachloride
Savatey [412]
I think the correct answer from the choices listed above is option 1. It would be the molecule carbon disulphide that will be polar, based on the structure of the choices given. Hope this answers the question. Have a nice day. Feel free to ask more questions.
4 0
3 years ago
Read 2 more answers
When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.
Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

\Delta T=32.3-25.0\ ^0C=7.3\ ^0C

So,  

\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J

Also, 1 J = 0.001 kJ

So,  

\Delta H=0.03189\ kJ

Also, Molar mass of CaO = 56.0774 g/mol

Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol

Thus, Enthalpy change in kJ/mol is:-

\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol

8 0
3 years ago
Which is the right answer?
Talja [164]

Answer:

i think its C

Explanation:

3 0
3 years ago
Phosphorus can be stable with 12 electrons in its valence structure while nitrogen can never have more than 8 electrons in its v
dolphi86 [110]

Here we have explain that the maximum possible electrons present in nitrogen valence shell is 8 whereas in phosphorous 12 valence electrons are present.

Although both nitrogen (N) and phosphorous (P) belongs to the same series there are several properties which are different between both the element. The number of electrons present in nitrogen is seven which are present in the -s and -p orbitals. The electronic configuration of nitrogen is 1s²2s²2p³. In which the outermost electrons are the valence electrons i.e. 5 valence electrons are present. The maximum orbitals are possible under the principal quantum number 2 are -s and -p orbitals. Now the maximum capacity of the p orbital to contain 6 electrons, as it is half filled in nitrogen another 3 electrons can be incorporated. Thus the maximum number of electrons can be present in nitrogen is 10 among which 8 is the valence electrons.

On the other hand there are 15 electrons in phosphorous the electronic configuration is 1s²2s²2p⁶3s²3p³. Now the principal quantum number 3 can have three orbitals -s, -p and -d. So another 13 electrons can be incorporated (3 in -p orbital and 10 in -d orbital) among which upto 12 electrons can be its valence electrons.

8 0
3 years ago
Calculate the boiling point of a solution of 500.0 g of ethylene glycol (c2h6o2) dissolved in 500.0 g of water. kf = 1.86°c/m a
Bingel [31]

Answer:The boiling point of the solution is 108° C.

Explanation:

Boiling point of pure water=T=100^oC

Boiling point of water after addition of 500 g of ethylene glycol=T_f

Mass of water = 500g = 0.5 kg (1000 g = 1 kg)

\Delta T_f=K_b\times \frac{\text{Mass of ethlyene glycol}}{\text{Molar mass of ethylene glycol}}

\Delta T_f=0.512^oC/m\times \frac{500 g}{62.07 g/mol\times 0.5 kg}

\Delta T_f=8.24 ^oC

\Delta T_f=T_f-T

8.24^oC=T_f-100^oC

T_f=108.24^oC

The boiling point of the solution is 108° C.

7 0
3 years ago
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