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Mandarinka [93]
3 years ago
11

(06.01)The tables below show four sets of data:

Mathematics
2 answers:
nika2105 [10]3 years ago
4 0

Answer: Set C is the only one!

Step-by-step explanation:

Yakvenalex [24]3 years ago
3 0
For it to be non-linear, the rate of change cannot be constant.  For the first table the rate is a constant 1 and the second table has a constant rate of -1.  The 3rd and 4th tables have no constant rate and thus are non-linear.

The 4th table is increasing while the 3rd table is decreasing.  

So the 3rd table, Set C, is the only non-linear negative association between x and y. 
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Find two numbers, if … b Their sum is −7 and their difference is 14
Delicious77 [7]

Answer:

x=0

y=-21/7

Step-by-step explanation:

Let the two unknown be x and y

x+y=-7...(1)

x-y=14...(2)

From (1) make x the subject of formula

x=-7-y...(3)

Substitute (3) into (2)

-7-y-y=14

-7-2y=14

Add 7 to both sides

-2y=21

Add both sides by-2

y=-21/2

Substitute the value of y into (3)

x=-7-(-21/2)

x=-7+21/3

Lcm

x=-21+21/3

x=0/3

x=0

4 0
3 years ago
Rewrite the following quadratic functions in intercept or factored form. Show your work.
Mariulka [41]

<u>Answer:</u>

y = 5x (x+2)

<u>Step-by-step explanation:</u>

We are given the following the quadratic function and we are to rewrite it in intercept or factored form:

y = 5x^2 + 10x

We can factorize the given expression so taking the common factors out of it to get:

y=5x^2 + 10x

y = 5x (x + 2)

Therefore, the factored form of the given quadratic function is y = 5x (x+2).

4 0
4 years ago
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Can you help me 2x+3y-x-(8+1)?
professor190 [17]

Answer: x+3y−9

Step-by-step explanation:

Simplify the expression.

I'd appreciate brainliest I need one more to get expert

8 0
3 years ago
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Harrizon [31]
Its b i had this question a minute ago

6 0
4 years ago
Is f(x) =8-5x find the value of f(2-k)
serg [7]

Answer:

5k - 2

Step-by-step explanation:

To evaluate f(2 - k), substitute x = 2 - k into f(x), that is

f(2 - k) = 8 - 5(2 - k) = 8 - 10 + 5k = 5k - 2

8 0
3 years ago
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