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Mandarinka [93]
3 years ago
11

(06.01)The tables below show four sets of data:

Mathematics
2 answers:
nika2105 [10]3 years ago
4 0

Answer: Set C is the only one!

Step-by-step explanation:

Yakvenalex [24]3 years ago
3 0
For it to be non-linear, the rate of change cannot be constant.  For the first table the rate is a constant 1 and the second table has a constant rate of -1.  The 3rd and 4th tables have no constant rate and thus are non-linear.

The 4th table is increasing while the 3rd table is decreasing.  

So the 3rd table, Set C, is the only non-linear negative association between x and y. 
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Karen works at a car dealership. She makes only $5 an hour, but for every car she sells, she makes $1,000 in commission. If Kare
kiruha [24]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
What is the equation of log x 729=3?
pishuonlain [190]

Answer:

Step-by-step explanation:

Move 729  to the left side of the equation by subtracting it from both sides.  x  3 − 729  = 0  Factor the left side of the equation.  Rewrite  729  as 9

3

.  x

3

−

9

3

=

0

. Since both terms are perfect cubes, factor using the difference of cubes formula,  a

3

−

b

3

=

(

a

−

b

)

(

a

2+ab+b2). Where a

=x and  b=9. (x−9)(x2+x⋅9+92)=0

. Simplify.  Move 9  to the left of x

.  (x−9)(x2+9x+92)=0.  Raise  9  to the power of 2

.  (x

−9

)(

x

2

+

9

x

+81

)=0

. Set x

−9  equal to  0 and solve for x.  Set the factor equal to  0. x−

9=

0. Add 9  to both sides of the equation.  x=9

. Set x2+

9

x

+

81 equal to  0  and solve for  x

.  Set the factor equal to 0

.  x2+9x+81=0.  Use the quadratic formula to find the solutions.  −b±√b2−4(ac) 2a. Substitute the values  a=1, b=9, and c=81  into the quadratic formula and solve for  x.  −9±√92−4⋅ (1⋅81

) 2⋅

1  Simplify.  Simplify the numerator. Raise 9  to the power of 2. x=−9±√81−4⋅(1⋅81) 2⋅1. Multiply  

81

by  

1

.

x

=

−

9

±

√

81

−

4

⋅

81

2

⋅

1

Multiply  

−

4

by  

81

.

x

=

−

9

±

√

81

−

324

2

⋅

1

Subtract  

324

from  

81

.

x

=

−

9

±

√

−

243

2

⋅

1

Rewrite  

−

243

as  

−

1

(

243

)

.

x

=

−

9

±

√

−

1

⋅

243

2

⋅

1

Rewrite  

√

−

1

(

243

)

as  

√

−

1

⋅

√

243

.

x

=

−

9

±

√

−

1

⋅

√

243

2

⋅

1

Rewrite  

√

−

1

as  

i

.

x

=

−

9

±

i

⋅

√

243

2

⋅

1

Rewrite  

243

as  

9

2

⋅

3

.

Tap for fewer steps...

Factor  

81

out of  

243

.

x

=

−

9

±

i

⋅

√

81

(

3

)

2

⋅

1

Rewrite  

81

as  

9

2

.

x

=

−

9

±

i

⋅

√

9

2

⋅

3

2

⋅

1

Pull terms out from under the radical.

x

=

−

9

±

i

⋅

(

9

√

3

)

2

⋅

1

Move  

9

to the left of  

i

.

x

=

−

9

±

9

i

√

3

2

⋅

1

Multiply  

2

by  

1

.

x

=

−

9

±

9

i

√

3

2

Factor  

−

1

out of  

−

9

±

9

i

√

3

.

x

=

−

1

9

±

9

i

√

3

2

Multiply  

−

1

by  

−

1

.

x

=

1

−

9

±

9

i

√

3

2

Multiply  

−

9

±

9

i

√

3

by  

1

.

x

=

−

9

±

9

i

√

3

2

The final answer is the combination of both solutions.

x

=

−

9

−

9

i

√

3

2

,

−

9

+

9

i

√

3

2

The solution is the result of  

x

−

9

=

0

and  

x

2

+

9

x

+

81

=

0

.

x

=

9

,

−

9

−

9

i

√

3

2

,

−

9

+

i

√

3

2

7 0
4 years ago
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
jolli1 [7]

Answer:

See explanation

Step-by-step explanation:

<h3 /><h3>Step 1</h3>

Miguel wins $2 is if he pulls two chips with the number 1.  

<u>Probability of winning is: </u>

  • 2/4 * 1/3 = 1/6  as there are 4 chips in total

<u> Probability of loosing is:</u>

  • 1- 1/6 = 5/6
<h3 /><h3>Step 2</h3>

<u>Missing values we found in the step 1, can be populated in the table:</u>

  • Xi === 2 === -1
  • P(Xi) === 1/6 === 5/6

<u>Expected Value as per table data:</u>

  • 1/6*2 + 5/6*(-1) = -1/2

Expected value is $1/2 loss each time he plays

<h3 /><h3>Step 3</h3>

To make the game fair, the expected value should be zero.

<u>Then as per the calculation above, let's replace 2, with x, and find its value.</u>

  • 1/6x + 5/6*(-1) = 0      
  • 1/6x = 5/6                  
  • x= 5  

So the amount should be $5 to make the game fair.

6 0
3 years ago
Find the 6th term in the sequence:100,60,36
IrinaK [193]

Answer:

Step-by-step explanation:100,60,36

hello :

the common ratio in the sequence:100,60,36  ( geometric sequence )

is : r = 60/36 = 36/100 = 0.6    the first term is : A1= 100

the n-ieme term is : An= A1× r ^(n-1)

An = 100× (0.6) ^(n-1)

the 6th term is : A6 = 100×(0.6)^5

4 0
3 years ago
Help with this plz? <br>Topic (Similarity)​
Darina [25.2K]

Answer:

MATH

Step-by-step explanation:

7 0
3 years ago
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