Answer:
λ₂ = 1.8 m
Explanation:
given,
wavelength of the string 1 = 0.90 m
frequency of the string 1 = 600 Hz
wavelength of string 2 = ?
frequency of the string 2 = 300 Hz
we now,
now,
λ₂ = 2 x 0.9
λ₂ = 1.8 m
Hence, the wavelength of the second string is equal to λ₂ = 1.8 m
Answer:
1.53 g
Explanation:
Given,
Initial speed = 30 m/s
Final speed = 0 m/s
Period of stretch, t = 2 s
average deceleration = ?
we know
a = -15 m/s²
Deceleration of the jumper = 15 m/s²
Deceleration in terms of g
Hence, the deceleration of the jumper is equal to 1.53 g
You need to move the decimal point between the six and nine. 6.9 X 10^-4
