Consider a 145 gram baseball being thrown by a pitcher. The ball approaches the batter with a speed of 44 m/s. The batter swings
1 answer:
For the development of this problem it is necessary to apply the concepts related to Force, momentum and time.
By definition we know that momentum can be expressed as
Where
P = Momentum
F = Force
t = Time
At the same time, another way of expressing the momentum is through mass and speed, that is,
P = mv
Where
m = Mass
v = Velocity
Equating both equations
F*t = mv
Our values are given as
Net velocity
Replacing we have then,
Therefore the average force exerted by the bat during the collision is 2223.3N
You might be interested in
Answer:
a) k = 200 N/m
b) E = 4 J
c) Δx = 6.3 cm
Explanation:
a)
- In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:
- where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).
- Solving for k:
b)
- Assuming no friction present, total mechanical energy mus keep constant.
- When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:
- Replacing k and Δx by their values, we get:
c)
- When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.
- We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).
- So, we can write the following expression:
- Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:
⇒
⇒