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ale4655 [162]
3 years ago
8

Consider a 145 gram baseball being thrown by a pitcher. The ball approaches the batter with a speed of 44 m/s. The batter swings

and sends the ball flying back at a speed of 90 m/s into the outfield.
If the ball was in contact with the bat for a time of 3 ms, what is the average force exerted by the bat during the collision?
Physics
1 answer:
larisa [96]3 years ago
4 0

For the development of this problem it is necessary to apply the concepts related to Force, momentum and time.

By definition we know that momentum can be expressed as

P = F*t

Where

P = Momentum

F = Force

t = Time

At the same time, another way of expressing the momentum is through mass and speed, that is,

P = mv

Where

m = Mass

v = Velocity

Equating both equations

F*t = mv

F = \frac{mv}{t}

Our values are given as

m = 145*10^{-3}Kg

t = 3*10^{-3}s

v = 90-44 = 46m/s \rightarrow Net velocity

Replacing we have then,

F = \frac{mv}{t}

F = \frac{3*10^{-3}*46}{3*10^{-3}}

F = 2223.33N

Therefore the average force exerted by the bat during the collision is 2223.3N

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