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4 years ago

The focal length is the distance from the lens (or mirror) to the: image object focal point center of curvature

Physics

2 answers:

Hatshy [7]4 years ago

7 0

Answer:

Focal length is the distance of center of the lens from its FOCAL POINT

Explanation:

As we know that when straight beam of light incident on the lens which is parallel to the principle axis of the lens then this light will get refracted by the lens

After the refraction from the lens the light will pass through the a point on the principle axis. That common point is known as FOCAL POINT.

As as per lens formula we know that

$\frac{1}{d_i}{ + \frac{1}{d_o} = \frac{1}{f}$

now we have

$d_o = infinite$

so here we have

$d_i = f$

so focal point will be the point where image formed when straight parallel beam of light passes through it.

galben [10]4 years ago

5 0

The answer is focal point.
The focal length is the distance from the lens (or mirror) to the focal point. The focal point is <span>the point at which rays of light converge.</span>

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Answer:

April to June

Explanation:

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3 years ago

A car traveling at 50 km/h hits a bridge abutment. A passenger in the car moves forward a distance of 61 cm (with respect to the

Karolina [17]

Answer:

6957.04N

Explanation:

Using

vf2=vi2+2ad

But vf = 0 .

So convert 50km/hr to m/s, and you need to convert 61 cmto m

(50km/hr)*(1hr/3600s)*(1000m/km) = 13.9m/s

61cm * (1m/100cm) = .61m

So n

0 = (13.9m/s)^2 + 2a(.61m)

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3 years ago

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When do phase transitions occur in molecules?

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3 years ago

Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west en

Brut [27]

Answer:

The corridor's distance is "90 m".

Explanation:

She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1.
Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled.
Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop.
The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.
Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.

Now,

⇒ $2x + 2y = 60$