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Vlada [557]
3 years ago
11

The focal length is the distance from the lens (or mirror) to the: image object focal point center of curvature

Physics
2 answers:
Hatshy [7]3 years ago
7 0

Answer:

Focal length is the distance of center of the lens from its FOCAL POINT

Explanation:

As we know that when straight beam of light incident on the lens which is parallel to the principle axis of the lens then this light will get refracted by the lens

After the refraction from the lens the light will pass through the a point on the principle axis. That common point is known as FOCAL POINT.

As as per lens formula we know that

\frac{1}{d_i}{ + \frac{1}{d_o} = \frac{1}{f}

now we have

d_o = infinite

so here we have

d_i = f

so focal point will be the point where image formed when straight parallel beam of light passes through it.

galben [10]3 years ago
5 0
The answer is focal point.
The focal length is the distance from the lens (or mirror) to the focal point. The focal point is <span>the point at which rays of light converge.</span>
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Absorbed

Explanation:

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stepan [7]

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3 years ago
What is the approximate mass of air in a living room 4.5m×3.4m×2.9m? the density of air is 1.29 kg/m3?
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First we have to calculate the volume of the living room:
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6 0
2 years ago
Two bodies of specific heats S1 and S2 having the same heat capacities are combined to form a single composite body. What is the
Dafna11 [192]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Heat capacity of body 1 :

\qquad \sf  \dashrightarrow \:m_1s_1

Heat capacity of body 2 :

\qquad \sf  \dashrightarrow \:m_2s_2

it's given that, the the head capacities of both the objects are equal. I.e

\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2

\qquad \sf  \dashrightarrow \:m_1 =  \dfrac{m_2s_2}{s_1}

Now, consider specific heat of composite body be s'

According to given relation :

\qquad \sf  \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2

\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }

[ since, m_2s_2 = m_1s_1 ]

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{  \cancel{m_2}(\frac{s_2}{s_1} + 1)}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 s_2}{  (\frac{s_2 + s_1}{s_1} )}

\qquad \sf  \dashrightarrow \: s' =  \dfrac{2s_1s_2}{s_1 + s_2}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

6 0
2 years ago
Read 2 more answers
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Bogdan [553]

Answer:

C) Plastic

Explanation:

Copper, silver, and gold all conduct electricity. Therefore, the material that would provide the most resistance for electricity would be plastic.

8 0
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