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Dvinal [7]
3 years ago
14

Tornadoes are most frequent from _____. April to June October to December January to March July to August

Physics
1 answer:
jenyasd209 [6]3 years ago
8 0

Answer:

April to June

Explanation:

Not really an explanation, I just know it.

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A ruby laser delivers a 16.0-ns pulse of 4.20-MW average power. If the photons have a wavelength of 694.3 nm, how many are conta
stepan [7]

Answer:

The  value is  n  =  2.347 *10^{17} \  photons

Explanation:

From the question we are told that

     The  amount of power delivered is  P  =  4.20 \  M W  =  4.20  *10^{6} \  W

      The  time taken is  t =  16.0ns  =  16.0 *10^{-9} \  s

       The  wavelength is  \lambda  =  694.3 \  nm =  694.3 *10^{-9} \  m

     

Generally the energy delivered is  mathematically represented as

     E  =  P  * t  =  \frac{n  *  h  *  c  }{\lambda }

Where  h is the Planck's constant with value  h  =  6.262  *10^{-34} \  J \cdot  s

           c  is the speed of light with value  c =  3.0*10^{8} \  m/s

     

So  

    4.20 *10^{6}  *  16*10^{-9}=  \frac{n  *  6.626 *10^{-34}  *  3.0*10^{8}  }{694.3 *10^{-9}}

=>    n  =  2.347 *10^{17} \  photons

4 0
3 years ago
How does the water cycle influence weather in your area? Use complete sentences and a specific example from your experience.
Charra [1.4K]

Evaporation is the process by which water changes from a liquid to a gas or vapor. Evaporation is the primary pathway that water moves from the liquid state back into the water cycle as atmospheric water vapor. Studies have shown that the oceans, seas, lakes, and rivers provide nearly 90 percent of the moisture in the atmosphere via evaporation, with the remaining 10 percent being contributed by plant transpiration.


5 0
3 years ago
Read 2 more answers
What type of force act on a man at room temperature and in a ground?
lakkis [162]
Isaac Newton’s second law of motion
6 0
3 years ago
The ozone the unearths surface from the dangerous radiation. This is an interaction between
Mnenie [13.5K]
The interaction is in the stratosphere.
7 0
3 years ago
An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el
Alborosie

Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

J=\frac{E}{\rho}      (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

J=\frac{I}{A}        (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}

Next, you replace for all variables:

I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A

hence, the current in the wire is 4.75A

4 0
3 years ago
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