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mel-nik [20]
3 years ago
6

Meg's pension plan is an annuity with a guaranteed return of 7% per year (compounded quarterly). She would like to retire with a

pension of $10,000 per quarter for 10 years. If she works 26 years before retiring, how much money must she and her employer deposit each quarter? HINT [See Example 5.] (Round your answer to the nearest cent.)
Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

Answer:

$985.92

Step-by-step explanation:

In order to solve this question, we are going to use two formulas.

Present Value of an Annuity

PV=PMT\frac{1-(1+i)^{-n} }{i}

To get the value of the pension of 10,000 per quarter for 10 years. And

Sinking funds Payments Formula

PMT=FV\frac{i}{(1+i)^{n}-1}

to get the Payment to be deposited each quarter during 26 years.

So for the first formula

n= number of periods = we need to know how many quarters in 10 years are. We know there are 4 quarters in a year, so 10 years multiplied by 4 is 40 quarters

n= 40

For i=interest rate= it is 7% compounded quarterly. There are 4 quarters so we divide by 4 and we get:

i=7%/4=1,75%

PMT= 10,000

PV=10,000\frac{1-(1+0.0175)^{-40} }{0.0175}\\\\PV=$285,942.30

and these 285,942.30 would be our future value in the sinking fund payment formula with:

n= 26 years *(4 quarters a year)= 104 quarters

i=1.75%

FV=$285,942.30

PMT=FV\frac{i}{(1+i)^{n}-1}\\\\PMT=285,942.30\frac{0.0175}{(1+0.0175)^{104}-1}\\\\PMT=985.92

And $985.92 would have to be deposited every quarter during 26 years to get a payment of $10,000 per quarter for 10 years.

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Lynn and dawn tossed a coin 60 times and got heads 33 times. What is the experimental probability of tossing heads using Lynn an
uysha [10]
The experimental probability would be 33 out of 60 or 55%
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3 years ago
Can you help me with this question please?
katovenus [111]

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Note: I will use L in place of x to represent the length of the prism.

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To find the surface area, use

A = bh + 2Ls + Lb

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15, 510 = (1/2)(60)(11)L

Can you finish? Just solve for L to find your x-value.

Part (b) set up:

To answer part (b), you must find the value of L in part (a).

A = (60)(11) + 2L(61) + L(60)

Understand? Take it from here.

5 0
3 years ago
Which is the completely factored form of 4x2 28x 49? (x 7)(4x 7) 4(x 7)(x 7) (2x 7)(2x 7) 2(x 7)(x 7)
natima [27]

The completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)

<h3>How to find the factors of a quadratic expression?</h3>

If the given quadratic expression is of the form ax^2 + bx + c, then its factored form is obtained by two numbers alpha( α ) and beta( β) such that:

b = \alpha + \beta \\ ac =\alpha \times \beta

Then writing b in terms of alpha and beta would help us getting common factors out.

Sometimes, it is not possible to find factors easily, so using the quadratic equation formula can help out without any  trial and error.

For this case, the given quadratic expression is:

4x^2 + 28x + 49

So we've to find two numbers such that:

Their sum = b =  28

Their product = ac = 4\times 49 = 196

We can see that 196 is square of 14, and that 14 added twice forms 28, thus:

14 + 14 = 28

14×14 = 196

Writing b = 28 as sum of 14 twice, we get:

4x^2 + 28x + 49 = 4x^2 + 14x + 14x +49 \\4x^2 + 28x + 49 =  2x(2x+7) + 7(2x + 7)\\4x^2 + 28x + 49  = (2x+7)(2x+7)

Thus, the completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)

Learn more about factorization of quadratic expression here:

brainly.com/question/26675692

8 0
2 years ago
What’s is 13.75 of 2/5
ivanzaharov [21]

Answer:

5.5

Step-by-step explanation:

Of means multiply

13.75 * 2/5

27.5/5

5.5

3 0
3 years ago
Read 2 more answers
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
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