Complete Question
Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
Answer:
The value is
Explanation:
From the question we are told that
The semi - major axis of the rocky debris 
The semi - major axis of Planet D is 
The orbital period of planet D is 
Generally from Kepler third law

Here T is the orbital period while a is the semi major axis
So

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=> ![T_R = 18.164 * [\frac{ 45}{60} ]^{\frac{3}{2} }](https://tex.z-dn.net/?f=T_R%20%20%3D%2018.164%20%20%2A%20%20%5B%5Cfrac%7B%2045%7D%7B60%7D%20%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D)
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Explanation:
The refraction is the change in the direction of light while travelling from the one medium to another due to having different speeds in different mediums.
To determine how much light gets refracted, it depends on the density of substance and the wavelength and the angle at which light enters the substance.
Light travels more slowly in denser medium than the rarer medium. The refractive index of glass is more than water or air. Light gets refracted more in this. When the light travels from rarer to denser then the light will get bend towards the normal. When the light travels from denser to rarer then the light will get bend away from the normal.
Glass is more denser than air or water. Water is more denser than the air. When light travels from air to glass then the light gets bends towards the normal. When the light travels from glass to the air then light gets bends away from the normal.
Therefore, the light gets refracted more in the glass than air to water.
Answer:
(A) 
Explanation:
Given:
Charge of one particle (q₁) = -0.0050 C
Charge of another particle (q₂) = 0.0050 C
Separation between them (d) = 0.025 m
We know that, from Coulomb's law, electric force acting between two charged particles is given as:

Plug in the given values and solve for electric force,
. This gives,

Therefore, option (A) is correct. Negative sign implies that the nature of electric force is attraction.
a) W=mg=833 N by definition
b) F=ma=76.5 N according to Newton's second law
c) a=F/m=4.12 m/s^2
d) m=F/a=720/5.5=130.91 kg