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Mamont248 [21]
4 years ago
8

How are light and sound waves affected by the different media they travel though?

Physics
1 answer:
seropon [69]4 years ago
8 0
Sound waves need to travel through a medium such as solids, liquids and gases. The sound waves move through each of these mediums by vibrating the molecules in the matter. The molecules in solids are packed very tightly. Liquids are not packed as tightly. And gases are very loosely packed. This enables sound to travel much faster through a solid than a gas. Sound travels about four times faster and farther in water than it does in air.

Light waves do not require a medium to travel. This is how light can travel through space and we can see stars. Light waves travel at a much higher velocity as compared to sound waves. The velocity of light waves (through a vacuum) is 3 xx 10^8 m/s. In comparison, the velocity of sound waves (in air) is about 343 m/s. Different frequencies of light waves give rise to different colors. On the other hand, different frequencies of sound waves result in different pitches. Light waves and sound waves have very different frequencies from each other. Sound waves have low frequencies (20 to 20,000 Hz) as compared to light waves (~ 10^14 Hz).
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It is raised to the height of 13.1 meters.

Explanation:

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A 1,500 kg car’s speed changes from 30 m/s to 15 m/s after the brakes are applied. Calculate the work done onto the car from the
HACTEHA [7]

The work done onto the car is 506,250 J

The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.

From the parameters given:

  • The mass of the car = 1500 kg
  • The initial speed = 30 m/s
  • The final speed = 15 m/s

The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)

\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}

\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}

\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}

= 506,250 J

Therefore, we can conclude that the work done on the car is 506,250 J

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3 years ago
Raul wants to increase his upper body and cardiovascular strength. He plans to go to the gym and use his backyard swimming pool
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How does wavelength change depending on whether the pipe is open or closed?
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Answer:

* in a tube with both ends open

        λ = 2L / n                    n = 1, 2, 3,…

* tube with one end open and the other closed.  

         λ = 4L / n                     n = (2n ’+ 1 )

Explanation:

When a sound wave enters a pipe, a resonance process occurs, whereby only some wavelengths can occur.

 

* in a tube with both ends open

in this case there are maximums at each end, so if the length of the had is L

              λ = 2L 1st harmonic

              λ = 2 L / 2 2nd harmonic

              λ = 2L / 3

              λ = 2L / n                    n = 1, 2, 3,…

* In the case of a tube with one end open and the other closed.

At the open end there is a belly and at the closed end a node

              λ = 4L 1st harmonic

              λ = 4L / 3 3rd harmonic

              λ = 4L / 5

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                                       n = (2n ’+ 1 )      where n’ are all integers

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