At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh So Energy given to rocket = mgh Energy expended by engine = F x D (D= height where engine stops) Energy 'lost' to drag is the difference between the two values. please if this helped mark it as the brainiest answer.
Answer:
70509.8039216 N/C
Explanation:
k = Coulomb constant = 
q = Charge = 2.00 µC
l = Length of filament = 5.1 m
r = Radius of cylinder = 10 cm
Electric field is given by
The electric field at the surface of the cylinder is 70509.8039216 N/C
Answer:
acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
SI unit: m/s2, m·s−2, m s−2
Here, K.E. = 1/2 * mv²
So, K.E. = 1/2 * (1200) * (24)²
K.E. = 1/2 * 1200 * 576
K.E. = 600 * 576
K.E. = 345,600 J
Hope this helps!
