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Nina [5.8K]
3 years ago
6

Which one of the following chemicals is most likely coming from the gas stove?

Chemistry
1 answer:
Eva8 [605]3 years ago
4 0
Here's a hint. One of these is a liquid, one is a gas, and one is a radioactive gas. Match each of these descriptions to the right element, and tell me which one you would be most likely to be emitted from your stove.
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What reaction is 2HI --> H2 + 12
Brilliant_brown [7]

Answer:

numbers

Explanation:

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3 years ago
1. Adakah benar bahawa anda tidak boleh membasuh rambut, meminum air sejuk dan
Ann [662]

Answer:

Adakah benar anda tidak boleh mencuci rambut, minum air sejuk dan

makan ais krim atau bersukan semasa haid? Terangkan jawapan anda.

Tidak, ini tidak benar, melakukan semua ini baik-baik saja. Seperti, tidak ada yang dapat mempengaruhi kita, kerana tidak bersambung dengan sistem kita. Juga, mohon maaf jika bahasa itu salah kerana saya menggunakan terjemahan Google.

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7 0
3 years ago
Hen the space shuttle blasts into orbit, a hot gas forms when hydrogen and oxygen join to make water. this helps the space shutt
sukhopar [10]

Answer: compound

Explanation:

3 0
3 years ago
Balance the equation and determine how many liter of nitrogen are required to react with 7.3 L of hydrogen to produce ammonia (n
Musya8 [376]

Answer:

4.867 L of ammonia

Explanation:

Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :

N₂ + 3H₂ → 2NH₃

Here, 3 moles of hydrogen gas gives 2 moles of ammonia.

1 mole of any substance occupies 22.4L at STP

So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia

Then 7.3 L of hydrogen will give:

=\frac{7.3 \times 2 \times22.4 }{3 \times22.4}

=\frac{7.3 \times 2}{3}

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3 0
3 years ago
Let's assume you were given 2.0 g benzil, 2.2 g dibenzyl ketone, 50 mL 95% ethanol and 0.3 g potassium hydroxide to synthesize t
almond37 [142]

Answer:

the % yield is 82%

Explanation:

Given the data in the question,

we know that;

Molar mass of benzil is 210.23 g·mol−1

Molar mass of dibenzyl ketone is 210.27 g·mol−1

Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1

Now,

2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole

2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole

3.0 g of tetraphenylcyclopentadienone = 3 / 384.5  = 0.0078 mole

Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone

percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%

= 0.82 × 100%

= 82%

Therefore, the % yield is 82%

3 0
3 years ago
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