Well for a start, this makes absolutely no sense, "discovered a fuel that burns so hot that it becomes cold."
<span>And yes, it's not science if the experiment can't be repeated. In fact they should WANT it to be repeated so that you can get credit for discovering something new and then possibly harness this effect to produce useful applications. </span>
<span>For all we know they had a fewer of LN2 in the lab that got shredded by the blast, LN2 could certainly have frozen many things (not metal though, since metal is already solid at room temperature, (except for mercury)), and afterwards would leave no trace.</span>
Answer:
296 L
Explanation:
We will need a balanced equation with moles, so let's gather all the information in one place.
4Al + 3O₂ ⟶ 2Al₂O₃
n/mol: 17.4
1. Moles of O₂
2. Volume of O₂
You haven't given the conditions at which the volume is measured, so I assume it is at STP (0 °C and 1 bar).
At STP the molar volume of a gas is 22.71 L.
Electronegativity<span> is the measure of the ability of an atom to attract electrons to itself. Fluorine is the most </span>electronegative<span> element and francium is one of the least</span>electronegative<span>. ... The </span>molecule's polarity<span> will be determined on the negative and positive regions on the outer atoms in the </span>molecule<span>.</span>
Answer:
65.08 g.
Explanation:
- For the reaction, the balanced equation is:
<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>
2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.
- Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:
<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>
<u><em>Using cross multiplication:</em></u>
2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.
0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.
∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.
<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol
) = <em>65.08 g.</em>
C) Sliver Carbonate AgCO3
