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Ilia_Sergeevich [38]
3 years ago
12

Identify the type of reaction represented by each equation.

Chemistry
2 answers:
UNO [17]3 years ago
7 0

1 - Synthesis

2 - Combustion

Chemical Reaction A is synthesis because both elements have synthesized into one, HCl.

Chemical Reaction B is combustion due to the fact that the products are carbon dioxide and water. A combustion reaction is a reaction that produces these products.

Hope this helps!

olganol [36]3 years ago
6 0

<u>Answer:</u> The correct answer is Synthesis and Combustion reaction.

<u>Explanation:</u>

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen to produce carbon dioxide and water.

\text{hydrocarbon}+O_2\rightarrow CO_2+H_2O

Decomposition reaction is defined as the chemical reaction in which a single substance breaks down into two or more simpler substances.

AB\rightarrow A+B

Double displacement reaction is defined as the chemical reaction in which exchange of ions takes place.

AB+CD\rightarrow AD+CB

Single displacement reaction is defined as the chemical reaction in which more reactive element displaces a less reactive element from its chemical reaction.

AB+C\rightarrow CB+A

Synthesis reaction is defined as the chemical reaction in which substances combine in their elemental state to form a single compound.

A+B\rightarrow AB

  • <u>For A:</u> H_2+Cl_2\rightarrow 2HCl

This reaction is considered as a synthesis reaction because hydrogen gas and chlorine gas are combining in their elemental states to produce hydrochloric acid molecule.

  • <u>For B:</u> CH_4+2O_2\rightarrow CO_2+2H_2O

This reaction is considered as a combustion reaction because methane gas is reacting with oxygen gas to produce carbon dioxide gas and water molecule.

Thus, the correct answer is Synthesis and combustion reaction.

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____ HBr + ____ Mg(OH)2 ---&gt; ____ MgBr2 + ____ H2O
swat32
Hello Camkirkland,
I think that you are trying to balance this equation.
In order to balance a chemical equation, the numbers of atoms of each element must be equal on both sides of the equation.

In this particular equation, the answer would be (2) HBr + (1) Mg(OH)2 ---> (1) MgBr2 + (2) H2O.

Hope this answers your question!
4 0
3 years ago
Is vineasel edible??????????????????????/
nevsk [136]

Answer:

no it's not edible

5 0
2 years ago
Read 2 more answers
When the gases dihydrogen monosulfide and oxygen react, they form the gases sulfur dioxide and water vapor. Write the balanced c
Anna35 [415]
2(H2S) + 3(O2) -> 2(SO2) + 2(H2O)
7 0
2 years ago
Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts
Y_Kistochka [10]

Answer:

Explanation:

Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts with oxygen. What is the limiting reactant in this experiment?

Mg + O2 → MgO (unbalanced)

first, balance the equation

2Mg +O2-------> 2MgO

two magnesium atoms react with one diatomic oxygen molecule

there is a 1:1 ratio of magnesium to oxygen atoms

but we have 2 moles of magnesium atoms and 2X5 = 10 moles of oxygen atoms

the lesser magnesium LIMITS the amount of product we can make, so it is the LIMITING REAGENT.

6 0
2 years ago
What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
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