The product formed when Ag2O decompose is O2 ( answer c)
explanation
Decomposition involve separation of a single chemical compound into two ore more elemental parts Ag2O decomposes to yield Ag and O2
that is 2Ag2O→ 4Ag + O2
2 moles of Ag2O decomposes to yield 4 moles of Ag and 1 mole of O2
The percentage yield obtained from the given reaction above is 74.8%
<h3>Balanced equation </h3>
P₄ + 6Cl₂ → 4PCl₃
Molar mass of P₄ = 31 × 4 = 124 g/mol
Mass of P₄ from the balanced equation = 1 × 124 = 124 g
Molar mass of PCl₃ = 31 + (35.5×3) = 137.5 g/mol
Mass of PCl₃ from the balanced equation = 4 × 137.5 = 550 g
<h3>SUMMARY</h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
<h3>How to determine the theoretical yield </h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
Therefore,
79.12 g of P₄ will react to produce = (79.12 × 550) / 124 = 350.9 g of PCl₃
<h3>How to determine the percentage yield </h3>
- Actual yield of PCl₃ = 262.6 g
- Theoretical yield of PCl₃ = 350.9 g
Percentage yield = (Actual /Theoretical) × 100
Percentage yield = (262.6 / 350.9) × 100
Percentage yield = 74.8%
Learn more about stoichiometry:
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Answer:

when there is a radical in the denominator, we should rationalize (mutiply the denominator and numerator by the radical) to get rid of the radical in the denominator.
B. At-200
In beta decay the atomic number increases by 1
Answer: 100C of heat is needed.
Explanation: That is the heating point of water