Question

Balance the equation and determine how many liter of nitrogen are required to react with 7.3 L of hydrogen to produce ammonia (nitrogen trihydride)?

Answer 1

Answer:

4.867 L of ammonia

Explanation:

Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :

N₂ + 3H₂ → 2NH₃

Here, 3 moles of hydrogen gas gives 2 moles of ammonia.

1 mole of any substance occupies 22.4L at STP

So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia

Then 7.3 L of hydrogen will give:

=$\frac{7.3 \times 2 \times22.4 }{3 \times22.4}$

=$\frac{7.3 \times 2}{3}$

= 4.867 L of ammonia