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ZanzabumX [31]
3 years ago
5

In a 10-gram sample of carbon and a 10-gram sample of sulfur, how many more moles of carbon are there than sulfur?

Chemistry
2 answers:
Lemur [1.5K]3 years ago
6 0

Answer : The more moles of carbon there than sulfur are, 0.52 moles.

Explanation : Given,

Mass of carbon = 10 g

Mass of sulfur = 10 g

Molar mass of carbon = 12 g/mol

Molar mass of sulfur = 32 g/mol

First we have to calculate the moles of carbon and sulfur.

\text{Moles of carbon}=\frac{\text{Given mass carbon}}{\text{Molar mass carbon}}

\text{Moles of carbon}=\frac{10g}{12g/mol}=0.833mol

and,

\text{Moles of sulfur}=\frac{\text{Given mass sulfur}}{\text{Molar mass sulfur}}

\text{Moles of sulfur}=\frac{10g}{32g/mol}=0.312mol

From this we conclude that,

Moles of carbon = 0.833 mol

Moles of sulfur = 0.312 mol

Difference between the moles of carbon and sulfur = 0.833 - 0.312 = 0.521 mol = 0.52 mol

Thus, the more moles of carbon there than sulfur are, 0.52 moles.

8_murik_8 [283]3 years ago
5 0
Your answer will be the second option

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Answer:

Check explanation.

Explanation:

Reductive amination is also known as reductive alkylation. Reductive amination is an good chemical reaction for the conversion of of carbonyl group into amine.

These are the steps to follow for the reaction;

(1). Step one: carbonyl group(either an aldehyde or a ketone) is used to convert amine to form an imine. The pH of the reaction should be slightly acidic.

(2). Step 2: the imine from step one is then converted into iminium ion under acidic condition too(for protonation).

(3). Step 3: the iminium ion is then reduced to the amine.

The equation of reaction are in the attached file.

Note: the attached picture is labelled (A) to (D).

Reaction A is the reaction of benzaldehyde with Benzylamine, B is the reaction of benzaldehyde with dibenzylamine, C is the reaction of benzaldehyde with N,N-Dimethylbenzylamine and D is the reaction of benzaldehyde with N-Benzylpiperidine.

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Answer:

The boiling point of the solution is 101,42ºC

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Tº boiling point solution - Tº boiling point = Ebulloscopic constant . molality . Van't Hoff factor.

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Molar mass NiSO4 = 154,75 g/m

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These moles are in 100 g of H2O, so we have to make a rule of three to find, the moles in 1000g

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Some of the applications of this effect include photomultipliers (which are a key component in spectroscopy instruments) and night vision devices.

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