Answer: 8moles
Explanation:
The reaction below shows the formation of 2 moles of water from 2 moles of hydrogen and 1 mole of oxygen respectively.
2H2(g) + O2 (g) --> 2H2O(l)
So, if 1 mole of O2 produce 2 mole of H2O
4 moles of O2 will produce Z mole of H2O
To get the value of Z, cross multiply
1 x Z = 4 x 2
Z = 8
So, the equation will be 8H2(g) + 4O2 (g) --> 8H2O(l)
Thus, 4 moles of O2 will produce 8moles of H2O .
Initial concentration of magnesium nitrate M1 = 2.13 M
Initial volume of magnesium nitrate, MgNO3 V1 = 1.24 L
Final concentration of MgNO3, M2 = 1.60 M
Let the final volume of MgNO3 upon dilution be V2
Formula to use:
M1*V1 = M2*V2
V2 = M1*V1/M2
= 2.13 M * 1.24 L/1.60 M = 1.65 L
Thus, the final volume of magnesium nitrate solution upon dilution is 1.65 L
It can be any row
Explanation:
An element with a valence electrons of 3 can be in any row on the periodic table.
The rows are the horizontal arrangement of elements on the periodic table.
Elements on the same row have the same energy level.
- The periodic table rows are called periods.
- It is only in the groups that we can find such element.
- Group 3 elements have 3 valence electrons.
- Since this group cuts through all the rows, therefore, elements with 3 valence electrons can be found in any row.
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Metalloids brainly.com/question/3023499
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Mass of oxygen = 143,1g - (53,4g + 16,9g + 43g) = 29,8g
If 143,1g ------ is ------ 100%
so
29,8g ------- is ------ %O
%O = (29,8g*100%) / 143,1g = 20,82%
