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choli [55]
3 years ago
6

10. Mario is making chocolate. In part of the chocolate-making process, he changed the phase from a liquid to a solid. What happ

ened to the molecules of chocolate when it changed phase?
a
Before changing phase, the molecules were moving around each other. After changing phase, they were moving away from each other.

b
Before changing phase, the molecules were moving around each other. After changing phase, they were moving in place.

c
Before the changing phase, the molecules were moving away from each other. After changing the phase, they were moving around each other.

d
Before changing phase, the molecules were moving in place. After changing phase, they were moving around each other.
Physics
1 answer:
Naily [24]3 years ago
6 0

Answer:

B

Explanation:

in a liquid the particles are widespread and move around each other but in a solid they move in place and are tightly packed

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Why are light-years more convenient than miles, kilometers, or astronomical units (au) for measuring the distances to stars and
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sEE BELOW

Explanation:

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5 0
2 years ago
in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's
GarryVolchara [31]

The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.

<h3>What is the Inverse Square Law formula?</h3>

The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}

Where

  • I₁ = Intensity at distance 1 (W/m²)
  • I₂ = Intensity at distance 2 (W/m²)
  • d₁ = distance 1 from a light source (m)
  • d₂ = distance 2 from a light source (m)

Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?

By using the inverse square law formula, the sun's intensity for an outer planet is

\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}

\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}

\frac{200 }{I_{2} } = \frac{36r^{2} }{r^{2}}

I_{2} = \frac{200} {36}

I₂ = 5.55 W/m²

Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².

Learn more about intensity of light here:

brainly.com/question/13155277

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3 0
1 year ago
Please help I'll mark brainliest NO LINKS
Bond [772]

Answer:C

Explanation:

7 0
3 years ago
A runner starts from rest and achieves a maximum speed of 8.85 m/s.
ycow [4]

Answer:

The appropriate answer is "0.9152 seconds".

Explanation:

The given values are:

Maximum speed,

v = 8.85 m/s

Acceleration,

u = 9.67 m/s²

Now,

⇒ v = u+at

By putting the values, we get

⇒ 8.85=0+9.67t

⇒      t=\frac{8.85}{9.67}

⇒         =0.9152 \ second    

5 0
3 years ago
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