His. Curbs I b h bs. H b u b
        
             
        
        
        
Answer:
sEE BELOW
Explanation:
Well.....because the numbers are 'astronomical'....meaning VERY, VERY , VERY LARGE 
 
        
             
        
        
        
The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.
<h3>What is the Inverse Square Law formula?</h3>
The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

Where
- I₁ = Intensity at distance 1 (W/m²)
- I₂ = Intensity at distance 2 (W/m²)
- d₁ = distance 1 from a light source (m)
- d₂ = distance 2 from a light source (m)
Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?
By using the inverse square law formula, the sun's intensity for an outer planet is




I₂ = 5.55 W/m²
Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².
Learn more about intensity of light here:
brainly.com/question/13155277
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Answer:
The appropriate answer is "0.9152 seconds".
Explanation:
The given values are:
Maximum speed,
v = 8.85 m/s
Acceleration,
u = 9.67 m/s²
Now,
⇒ 
By putting the values, we get
⇒ 
⇒      
⇒         