Assume that the number of adult tickets is a and the number of child tickets is c.
We are given that the adult ticket is sold for 20$, the child ticket is sold for 10$ and that the total is $15,000. This means that:
20a + 10c = 15,000 ..........> equation I
We are also given that number of child tickets is 3 times that of adult's. This means that:
c = 3a .........> equation II
Substitute with equation II in equation I to get a as follows:
20a + 10c = 15,000
20a + 10(3a) = 15,000
20a + 30a = 15,000
50a = 15,000
a = 300 tickets
Substitute with the value of a in equation II to get c as follows:
c = 3a
c = 3(300)
c = 900 tickets
Based on the above calculations,
number of child tickets = 900 ticket
number of adult tickets = 300 ticket
Start by distributing -5x into x then into -3y. So -5x times x equals -5x^2( -5x squared), then -5 times -3y, equals 15xy so your answer is -5x^2 + 15xy.
So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x
WAIT WAIT NO I'M WRONG FORGIVE ME!
It's x=a/2(1+3z)
24 * 3/4 = 18
The radius of smaller cone is 3/4 the radius of original cone, so since these cones are similar, height must also be 3/4 times smaller.
So since radius is squared and we also multiple the height (V = 1/3 π r² h),
the volume of smaller cone would be 3³ / 4³ = 27 / 64 times smaller
So we have 1920 * (27 / 64) = 810.
Final answer: B
