Question

Calculate the average velocity of the cart for each fan speed. Round your answers to the nearest tenth.

Answer 1

Explanation:

The cart with Low fan speed :

Elapsed time to finish line, t = 7.4 s

Total distance, d = 500 cm

Average speed,

$v=\dfrac{d}{t}$

$v=\dfrac{500\ cm}{7.4\ s}$

v = 67.56 cm/s

or

v = 67.6 cm/s

The cart with Medium fan speed :

Elapsed time to finish line, t = 6.4 s

Total distance, d = 500 cm

Average speed,

$v=\dfrac{d}{t}$

$v=\dfrac{500\ cm}{6.4\ s}$

v = 78.12 cm/s

v = 78.1 cm/s

The cart with High fan speed :

Elapsed time to finish line, t = 5.5 s

Total distance, d = 500 cm

Average speed,

$v=\dfrac{d}{t}$

$v=\dfrac{500\ cm}{5.5\ s}$

v = 90.90 cm/s

or

v = 90.9 cm/s

Hence, this is the required solution.

Answer 2

Answer:

Answers in the explanation

Explanation:

The term speed is used to denote distance  traveled divided by time. This can be expressed in a mathematical language as follows:

$v=\frac{d}{t} \\ \\ \\ v:speed \\ \\ d:distance \\ \\ t:time$

The cart with Low fan speed:

$v=\frac{500}{7.4} \\ \\ v=67.5675cm/s \\ \\ Rounding \ to \ the \ nearest \ tenth: \\ \\ \boxed{v=67.6cm/s}$

The cart with Medium fan speed:

$v=\frac{500}{6.4} \\ \\ v=78.125cm/s \\ \\ Rounding \ to \ the \ nearest \ tenth: \\ \\ \boxed{v=78.1cm/s}$

The cart with High fan speed:

$v=\frac{500}{5.5} \\ \\ v=90.9090cm/s \\ \\ Rounding \ to \ the \ nearest \ tenth: \\ \\ \boxed{v=90.9cm/s}$