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guajiro [1.7K]
3 years ago
9

Please need help with this

Physics
1 answer:
Mademuasel [1]3 years ago
8 0

A 'velocity' is built out of a speed and a direction.

The only item on that list that has a speed and a direction is the <em>first one</em>.  The speed is 30 m/s and the direction is south.

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A car covers a distace of 20km in 20 seconds. Calculate its speed in km/h m/s.​
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Answer:

speed = 3600 kilometers per hour

= 3600 km/h

speed = 1000 meters per second

= 1000 m/s

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Coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m
jeka57 [31]

Answer:

V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s     average speed

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Which of the following can explains convection?
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What are the highlands of the moon called?<br> A) Maria<br> B) Terrae<br> C)Regolith<br> D)Crater
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8 0
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A batch of 75 parts is to be nickel-plated in a barrel plating operation. The parts are identical, each with a surface area A =
mojhsa [17]

To solve this problem it is necessary to take into account the concepts related to electrochemical Machining Processes and metal removal. Metal removal rate is determined by Faraday's First law, which states that the amount of chemical change Produced by an electric current is proportional to the quantity of electricity passed, i.e,

V = CIt

Where,

V = Volume of material removed

C = Constant called the specific removal rate that depends on atomic weight (I attached a table with this values)

I = Current

t = time

Since we also have to consider the efficiency of the system to remove the Volume, of all the volume removed, only 95% will be efficient.

From our values we have to

A = 5.3in^2

I = 120A

t = 20 min

C = 1.25*10^{-4} in^3/A-min

\eta = 95%

Calculating the value we have that,

V = (1.25*10^{-4})(120)(20)

V = 0.3in^3

V_{net} = 95\% *0.3

V_{net} = 0.285in^3

The area is simply the calculation of the total units by that of each piece, that is

A = 75*5.3

A = 397.5in^2

Therefore we can calculate now the plating thickness through the ratio between Volume and Area

d = \frac{V}{A}

d = \frac{0.285}{397.5}

d = 0.000716in

Therefore the average plating thickness on the parts is 0.000716in

7 0
3 years ago
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