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3 years ago

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A taxi charges $1.75 plus a fee of $0.75 for each mile traveled.the total coast of a ride without a trip is $4.75 how many miles

is the trip use m for the number of miles traveled

1 answer:

Alisiya [41]3 years ago

5 0

y = .75x + 1.75

4.75 = .75x + 1.75

4.75 - 1.75 = 3

3 = .75x

3/.75 = 4

The trip is 4 miles.

m = 4

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LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

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so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

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2 years ago

You spent $175 on a pair of shoes and three shirts. Each shirt cost the same amount. The shoes cost four times the amount of one

sergey [27]

Step-by-step explanation:

1. making the equation:

shoes = x

shirts = y

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x = 4y

2. graph it (I'm using desmos)

the green line is for 175 = x + 3y and the purple one is for x = 4y

3. find the price

x = 4y

175 = 4y + 3y

175 = 7y

y = 175/7 = $25

price of the shirt = $25

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3 years ago

Solve for m: 18d − 2m + 9k < 5k + 10

snow_tiger [21]

$18d-2m+9k$ < $5k+10$

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3 years ago

Read 2 more answers

Wind farm configuration is a significant issue as the upwind turbines generate maximal energy while creating wakes for downwind

lord [1]

Answer:

a) [24.114,29.2858]

b) Since 30 is not in the 95% confidence interval, there is a 95% probability that 30 is not the true mean WEP

Step-by-step explanation:

a)

The 95% confidence interval is given by the interval

$\bf [ \bar x-z^*\frac{s}{\sqrt n}, \bar x+t^*\frac{s}{\sqrt n}]$

where

$\bf \bar x$ = 26.7 is the sample mean

s = 17.7 is the sample standard deviation

n = 180 is the sample size

Since the sample size is big enough, we can use the Normal N(0,1) to compute $\bf z^*$ and it would be 1.96(*) (a value such that the area under the Normal curve outside the interval [-z, z] is 5% (0.05))

and our 95% confidence interval is

$\bf [26.7-1.96*\frac{17.7}{\sqrt{180}}, 26.7+1.96*\frac{17.7}{\sqrt{180}}]=\boxed{[24.114,29.2858]}$

(*)

This value can be computed in Excel with

<em>NORMINV(1-0.025,0,1)</em>

and in OpenOffice Calc with

<em>NORMINV(1-0.025;0;1)</em>

b)

Since 30 is not in the 95% confidence interval, there is a 95% probability that 30 is not the true mean WEP

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koban [17]

WORK

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3 years ago