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balandron [24]
3 years ago
8

Why is platinum metal preferred to other metals for the flame test​

Chemistry
2 answers:
Mama L [17]3 years ago
8 0

Answer:

Platinum is especially good for this because it is unreactive, and does not produce a color in the flame which will mask the presence of other metals.

Hope this answer is right!

sweet [91]3 years ago
4 0

Answer:

<em>Hey</em><em> </em><em>mate</em><em>,</em><em> </em><em>here</em><em> </em><em>is</em><em> </em><em>your</em><em> </em><em>answer</em>

1. Platinum doesn't impart any color to the flame.

2. It is not oxidised under the high temperature of the flame from a bunsen burner.

3. It is almost chemically inert. Even at high temperatures, it remains unattacked by free radicals / acid radicals.

Therefore, platinum wire is crucial for a flame test. Also, a platinum wire should be thoroughly cleaned before using it for a new flame test.

A platinum wire is cleaned by dipping it into concentrated HNO3 and then placing it in the non luminous part of the bunsen flame. Otherwise, the perviously tested radicals will impart color to the flame, which may cause confusion.

Explanation:

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>you</em><em> </em>

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A glass sphere is filled to full volume with a gas. The pressure of the gas inside the sphere is 30.0 atm, and the temperature i
harkovskaia [24]

Answer:

28atm

Explanation:

Using Gay lussac's law equation as follows:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

Based on the information provided in this question;

P1 = 30.0 atm, T1 = 30.0°C, P2 = ?, T2 = 10.0°C

NOTE: Absolute temperature i.e. Kelvin is required for this law

T1 = 30°C + 273K = 303K

T2 = 10°C + 273K = 283K

Using P1/T1 = P2/T2

30/303 = P2/283

Cross multiply

P2 × 303 = 30 × 283

303P2 = 8490

P2 = 8490/303

P2 = 28.02

New pressure of the gas = 28atm

4 0
3 years ago
Whenever a number or a variable is divided<br> by itself, it is always equal to
Jobisdone [24]

Answer:itself

Explanation:

Duh

5 0
3 years ago
What are the two variables that affect the electric force between two objects?
givi [52]

Explanation:

The electrical force between two objects is given by the formula as follows :

F=\dfrac{kq_1q_2}{d^2}

k is electrostatic constant

q₁ and q₂ are electric charges

d is distance between charges

So, the two force between two charged objects depends on the product of charges and distance between charges.

5 0
3 years ago
Phosgene, a poisonous gas, when heated will decompose into carbon monoxide and chlorine in a reversible reaction: COCl2 (g) &lt;
Advocard [28]

Answer:

8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

The initial concentration of phosgene is:

M = 2.00 mol / 1.00 L = 2.00 M

We can find the final concentrations using an ICE chart.

     COCl₂(g) ⇄ CO (g) + Cl₂(g)

I       2.00            0            0

C        -x             +x           +x

E    2.00 -x          x             x

The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

[CO] = [Cl₂] = 0.0398 M

The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

Keq = (0.0398)²/1.96

Keq = 8.08 × 10⁻⁴

4 0
3 years ago
Helppppp pls it’s due by today
Andrews [41]

Answer:

i can't see the picture

Explanation:

4 0
3 years ago
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