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GREYUIT [131]
3 years ago
12

Wednesday

Chemistry
1 answer:
hodyreva [135]3 years ago
4 0

Answer: B.

Explanation: Volcanoes

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Calculate the number of atoms per cubic meter in aluminum. The density and atomic weight of aluminum are 2.70 g/cm3 and 26.98 g/
olya-2409 [2.1K]

Answer:

The number of Aluminium atoms present in per cubic meter is N=6.02\times 10^{28}\ atoms/m^3

Explanation:

Given the density of Aluminium (\rho ) is 2.70\ g/cm^3

And the atomic weight of Aluminium (A_{Al}) is 26.98\ g/mol

Also, the Avogadro's number (N_A) is 6.023\times 10^{23}\ atoms/mol

We need to find the number of atoms per cubic meter (N)

N=\frac{\rho N_{A}}{A_{Al}}

Plug the given values in the formula we get,

N=\frac{2.70\times 6.022\times 10^{23}}{26.98}\\ \\N=0.602\times 10^{23}\ atoms/cm^3\\N=6.02\times 10^{22}\ atoms/cm^3\\N=6.02\times 10^{22}\times10^6\ atoms/m^3

N=6.02\times 10^{28}\ atoms/m^3

So, the number of Aluminium atoms present in per cubic meter is N=6.02\times 10^{28}

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4 years ago
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Why is plastic not classified as a composite?
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As in math or 
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3 years ago
In a solution, the substance that changes phase is the _____, while the substance that does not change phase is the____.
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1. 100gm of a 55% (M/M) nitric acid solution is to be diluted to 20% (M/M) nitric acid.
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Answer:

The volume of water to be added is 0.175 liters of water

Explanation:

The given concentration of the nitric acid = 55% (M/M)

The mass of the nitric acid solution = 100 gm

The concentration solution is to diluted to = 20% (M/M)

The 100 g 55%(M/M) nitric acid solution gives 55g nitric acid in 100 g of solution

Therefore, to have 20% (M/M) nitric acid solution with the 55 g nitric acid, we get

Let "x" represent the volume of the resulting solution, we have;

20% of x = 55 g of nitric acid

∴ 20/100 × x = 55 g

x = 55 g × 100/20 =  275 g

The mass of extra water to be added = The mass of the 20%(M/M) solution solution of nitric acid - The current mass of the 55%(M/M) solution of nitric acid

The mass of extra water to be added = 275 g - 100 g = 175 g

Volume = Mass/Density

The density of water ≈ 1 g/ml

∴ The volume of water to be added that gives 175 g of water =  175 g/(1 g/ml) = 175 ml. = 0.175 l

The volume of water to be added = 0.175 liters of water.

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