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3 years ago

Solve the system of linear equations using the elimination method x=3y;3x-2y=14

Mathematics

1 answer:

vladimir1956 [14]3 years ago

7 0

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x=3y&\text{subtract}\ 3y\ \text{from both sides}\\3x-2y=14\end{array}\right\\\\\left\{\begin{array}{ccc}x-3y=0&\text{multiply both sides by (-3)}\\3x-2y=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-3x+9y=0\\3x-2y=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad7y=14\qquad\text{divide both sides by 7}\\.\qquad\qquad y=2\\\\\text{put the value of y to the first equation:}\\x=3(2)=6$

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What is the variables on both sides equations? 3x - 6 = 7x + 1

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Pleaseeeee anyone want to help me on this??? WILL MARK BRIANLIEST

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Answer:

The Length of JK is 10

Step-by-step explanation:

Because <J is congruent to <L we know that the triangle in question must be isosceles as in an isosceles triangle two angles opposite of each other are equal. (This is also true for equilateral triangles, however, in an equilateral triangle all sides must be congruent, so we can rule equilateral out as LJ is not congruent to KL.) This means that the triangle must be isosceles.

In an isosceles triangle the side opposite each other are congruent, and the angles opposite each other are congruent when split down the line of symmetry.

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