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jeyben [28]
3 years ago
9

The steps in the formation of sedimentary rocks are listed below in an incorrect order.

Physics
2 answers:
NNADVOKAT [17]3 years ago
7 0
<h3><u>Answer;</u></h3>

c. 1, 4, 3, 2

<h3><u>Explanation;</u></h3>
  • <em><u>Sedimentary rocks are among the three major types of rocks, others being igneous rocks and metamorphic rocks. Sedimentary rocks result from the deposition and cementation of minerals or organic particles on the ocean floor or other water bodies on the surface of the earth.</u></em>
  • Sedimentary rocks are formed through the following steps;

<em>1) weathering of preexisting rocks, </em>

<em>2) transport of the weathering products, </em>

<em>3) deposition of the material, then</em>

<em>4) compaction, and</em>

<em>5) cementation of the sediment to form a rock</em>.

Arlecino [84]3 years ago
5 0
The first step in the formation of sedimentary rock is weathering of preexisting rocks. The second step is transport of the weathering products. The third step is deposition of the material. And at the end there is compaction and cementation of the sediment to form a rock.
According to this, the following shows the correct order of steps in the formation of sedimentary rocks:
C. <span>1, 4, 3, 2
</span>Rocks are weathered.Small pieces of rocks are carried by water.They are deposited in layers.<span>The sediments are compacted together.</span>
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Marina is staring at an optical illusion where he sees a version of the American flag that is colored green, yellow, and black.
k0ka [10]

Explanation:

The reason why Marina sees the colour red, white and blue or the original colour of the American flag is that because of a phenomenon known as Afterimage. The retina in our eyes have mainly three receptors that are colour sensitive known as cones. These receptors can perceive the colour green, red and blue. Now when we look or stare at a particular colour for a long time, what happen is that our retina becomes tired and they ignore the colours that stared at. And now they work to form other colours at the retina just like the way when we produce other colour from the primary colour.

If the red receptor gets exhausted we will see the colour red. Likewise when we see the colour orange when we stare at the colour blue.

This explains the optical illusion of the American flag.

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3 years ago
Does heat always give of heat
iren2701 [21]
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3 0
3 years ago
Read 2 more answers
A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has radius 11.0 cm ,
viktelen [127]
Part A)
First of all, let's convert the radii of the inner and the outer sphere:
r_A = 11.0 cm = 0.110 m
r_B = 16.5 cm=0.165 m
The capacitance of a spherical capacitor which consist of two shells with radius rA and rB is
C=4 \pi \epsilon _0  \frac{r_A r_B}{r_B- r_A}=4\pi(8.85 \cdot 10^{-12}C^2m^{-2}N^{-1}) \frac{(0.110m)(0.165m)}{0.165m-0.110m}=
=3.67\cdot 10^{-11}F

Then, from the usual relationship between capacitance and voltage, we can find the charge Q on each sphere of the capacitor:
Q=CV=(3.67\cdot 10^{-11}F)(100 V)=3.67\cdot 10^{-9}C

Now, we can find the electric field at any point r located between the two spheres, by using Gauss theorem:
E\cdot (4 \pi r^2) =  \frac{Q}{\epsilon _0}
from which
E(r) =  \frac{Q}{4 \pi \epsilon_0 r^2}
In part A of the problem, we want to find the electric field at r=11.1 cm=0.111 m. Substituting this number into the previous formula, we get
E(0.111m)=2680 N/C

And so, the energy density at r=0.111 m is
U= \frac{1}{2} \epsilon _0 E^2 =  \frac{1}{2} (8.85\cdot 10^{-12}C^2m^{-2}N^{-1})(2680 N/C)^2=3.17 \cdot 10^{-5}J/m^3

Part B) The solution of this part is the same as part A), since we already know the charge of the capacitor: Q=3.67 \cdot 10^{-9}C. We just need to calculate the electric field E at a different value of r: r=16.4 cm=0.164 m, so
E(0.164 m)= \frac{Q}{4 \pi \epsilon_0 r^2}=1228 N/C

And therefore, the energy density at this distance from the center is
U= \frac{1}{2}\epsilon_0 E^2 =  \frac{1}{2} (8.85\cdot 10^{-12}C^2m^{-2}N^{-1})(1228 N/C)^2=6.68 \cdot 10^{-6}J/m^3
8 0
3 years ago
Which of the following has least mass
makvit [3.9K]
Answer is 1 molecule of S
4 0
2 years ago
A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The ang
olga55 [171]

Answer:

9.22 s

Explanation:

One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad

Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:

For the child: s_c = \omega_ct = 0.233t

For the horse: s_h = s_0 + a_ht^2/2 = 1.57 + 0.0136t^2/2 = 1.57 + 0.0068t^2

For the child to catch up with the horse, they must cover the same angular distance within the same time t:

s_c = s_h

0.233t = 1.57 + 0.0068t^2

0.0068t^2 - 0.233t + 1.57 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{0.233\pm \sqrt{(-0.233)^2 - 4*(0.0068)*(1.57)}}{2*(0.0068)}

t= \frac{0.233\pm0.11}{0.0136}

t = 25.05 or t = 9.22

Since we are looking for the shortest time we will pick t = 9.22 s

6 0
3 years ago
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