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Anna35 [415]
3 years ago
10

Vicky wanted to investigate water evaporation. She placed 50 mL of distilled water in three identical glass jars. She left one j

ar in the sunlight, one jar in the dark, and one jar in a shady area. After four hours, she measured how much water was still in each jar. Which of the following variables was held constant in the experiment? A. air temperature B. amount of water in jars at the end of the investigation C. light exposure D. amount of water placed in jars
Physics
2 answers:
IgorC [24]3 years ago
4 0

Answer:

D. the amount of water placed in jars

Explanation:

it was the same for all of the jars at the beginning

Korolek [52]3 years ago
3 0
D because it makes the most sense
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The density of seawater at a depth where the pressure is 500 atm is 1124kg/m^3

Explanation:

The relationship between bulk modulus and pressure is the following:

B=\rho_0 \frac{\Delta p}{\Delta \rho}

where

B is the bulk modulus

\rho_0 is the density at surface

\Delta p is the variation of pressure

\Delta \rho is the variation of density

In this problem, we have:

B=2.3\cdot 10^9 N/m^2 is the bulk modulus

\rho_0 =1100 kg/m^3

\Delta p = p-p_0 = 500 atm - 1 atm = 499 atm = 5.05\cdot 10^7 Pa is the change in pressure with respect to the surface (the pressure at the surface is 1 atm)

Therefore, we can find the density of the water where the pressure is 500 atm as follows:

\rho = \rho_0 + \Delta \rho = \rho_0+\frac{\rho_0 \Delta p}{B}=\rho_0 (1+\frac{\Delta p}{B})=(1100)(1+\frac{5.05\cdot 10^7}{2.3\cdot 10^9})=1124kg/m^3

Learn more about pressure in a fluid:

brainly.com/question/9805263

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Cellular respiration can be simply expressed as shown below:

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