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sleet_krkn [62]

3 years ago

13

A moving car has kinetic energy. If it speeds up until it is going four times faster than before, how much kinetic energy does i

t have in comparison?

1 answer:

Eva8 [605]3 years ago

7 0

<h2>Ratio of final kinetic energy to initial kinetic energy is 16.</h2>

Explanation:

Kinetic energy , KE = 0.5mv²

Here car speeds up to four times the initial speed, we need to find ratio of final kinetic energy to initial kinetic energy.

Final speed = 4 x Initial speed = 4v

Initial KE = 0.5mv²

Final KE = 0.5 x m x (4v)²

Final KE = 16 x 0.5 x m x v²

Final KE = 16 x Initial KE

Ratio of final kinetic energy to initial kinetic energy is 16.

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g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?

beks73 [17]

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

$F = \sqrt{F_x^2 + F_y^2}$

$F = \sqrt{5.69^2 + 8^2}$

$F = \sqrt{32.3761 + 64}$

$F = \sqrt{96.3761}$

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

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A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?

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A reference point would be something not on the ship which could be used to calculate distance traveled.

Answer: C.) A lighthouse on a nearby Island

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A. Which of the four thermal processes describes the pressure-volume relationship at a constant temperature?

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Boyles law describes pressure volume relationship at constant temperature pressure is directly proportional to volume at constant tamparature

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A tall cylinder contains 30 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t

Anastaziya [24]

Answer:

The gauge pressure is $P_g = 2058 \ P_a$

Explanation:

From the question we are told that

The height of the water contained is $h_w = 30 \ cm = 0.3 \ m$

The height of liquid in the cylinder is $h_t = 40 \ cm = 0.4 \ m$

At the bottom of the cylinder the gauge pressure is mathematically represented as

$P_g = P_w + P_o$

Where $P_w$ is the pressure of water which is mathematically represented as

$P_w = \rho_w * g * h_w$

Now $\rho_w$ is the density of water with a constant values of $\rho_w = 1000 \ kg /m^3$

substituting values

$P_w = 1000 * 9.8 * 0.3$

$P_w = 2940 \ Pa$

While $P_o$ is the pressure of oil which is mathematically represented as

$P_o = \rho_o * g * (h_t -h_w )$

Where $\rho _o$ is the density of oil with a constant value

$\rho _o = 900 \ kg / m^3$

substituting values

$P_o = 900 * 9.8 * (0.4 - 0.3)$

$P_o = 882 \ Pa$

Therefore

$P_g = 2940 - 882$

$P_g = 2058 \ P_a$

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Does uniform acceleration means increasing acceleration?

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