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ziro4ka [17]
3 years ago
6

Which prefix is needed when naming SO3?

Chemistry
1 answer:
Karolina [17]3 years ago
8 0
The formula shows that molecule is made of one sulfur atom and three oxygen atoms. This means that the prefix used should be 'tri'. This means three and the substance would be called sulfur trioxide. A molecule with two oxygen atoms would be named sulfur dioxide. The nomenclature of chemicals often uses prefixes so the name itself can give a picture of what it is made of.
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if the fundamental frequency of a certain string is 84 hz, what is the frequency of the second harmonic? 42 hz 84 hz 126 hz 168
makkiz [27]
Fundamental frequency, f₀ = 84 Hz

Second harmonic is  2f₀ = 2* 84 Hz = 168 Hz
3 0
4 years ago
Read 2 more answers
Calculate the number-average molecular weight of a random nitrile rubber [poly(acrylonitrile-butadiene) copolymer] in which the
SCORPION-xisa [38]

Answer:

106,504 g/mol

Explanation:

The two repeat units at the polymer are the acrylonitrile and the butadiene. If the fraction of repeat of butadiene is 0.27, the fraction of repeat of units of acrylonitrile must be 0.73.

The acrylonitrile repeat unit has 3 carbons atoms, 1 nitrogen atom, and 3 hydrogen atoms. So, the molecular weigth for it is:

mac = 3*mC + 1*mN + 3*mH

mC = 12 g/mol; mN = 14 g/mol; mH = 1g/mol

mac = 3*12 + 14 + 3*1 = 53 g/mol

The butadiene repeat unit has 4 carbons atoms and 6 hydrogen atoms. Thus, the molecular weight is:

mbu = 4*12 + 6*1 = 54 g/mol

The average repeat unit molecular weight is the fractions multiplied by the molecular weight of the repeat unities:

m = 0.73*53 + 0.27*54 = 53.27 g/mol

The number-average molecular weight is the average repeat unit molecular weight  multiplied by the degree of polymerization:

M = 53.27*2000

M = 106,504 g/mol

7 0
3 years ago
A horizontal row on the periodic table is known as a _____. group family period list
Mekhanik [1.2K]
Period.  Groups/families are the vertical columns on the periodic table.
6 0
3 years ago
Read 2 more answers
One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from t
larisa [96]
The balanced chemical equation is written as:

<span>CsF(s) + XeF6(s) ------> CsXeF7(s)

We are given the amount of </span>cesium fluoride and <span>xenon hexafluoride used for the reaction. We need to determine first the limiting reactant to proceed with the calculation. From the equation and the amounts, we can say that the limiting reactant would be cesium fluoride.  We calculate as follows:

11.0 mol CsF ( 1 mol </span>CsXeF7 / 1 mol CsF ) = 11.0 mol <span>CsXeF7</span>
6 0
3 years ago
Read 2 more answers
Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
lisov135 [29]

Answer:

Concentration: 0.185M HX

Ka = 9.836x10⁻⁶

pKa = 5.01

Explanation:

A weak acid, HX, reacts with NaOH as follows:

HX + NaOH → NaX + H2O

<em>Where 1 mole of HX reacts with 1 mole of NaOH</em>

To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).

18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX

In 20.0mL = 0.0200L =

0.00370 moles HX / 0.0200L = 0.185M HX

The equilibrium of HX is:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

And Ka is defined as:

Ka = [H⁺] [X⁻] / [HX]

<em>Where [H⁺] = [X⁻] because comes from the same equilibrium</em>

As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M

Replacing:

Ka = [H⁺] [H⁺] / [HX]

Ka = [1.349x10⁻³M]² / [0.185M]

Ka = 9.836x10⁻⁶

pKa = -log Ka

<h3>pKa = 5.01</h3>
6 0
3 years ago
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