A graduated cylinder is filled with 54.32 cm3 of water. An irregular solid made of iron is carefully placed into the graduated c
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Measured volume = 10 ml
mass = 9.925 g
density = 0.9975 g/ml
density =
so actual volume =
= 
= 9.95 mL
Percentage Error =
x 100
=
x 100 = 0.5 % error
mass = 9.925 g
density = 0.9975 g/ml
density =
so actual volume =
Percentage Error =
=
Answer : The oxidizing element is N and reducing element is O.
is act as an oxidizing agent as well as reducing agent.
Explanation :
An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.
Reducing agent is the agent which has ability to reduce other or lower in oxidation number.
The given reaction is :
act as an oxidizing agent.
The oxidation number of N in is calculated as:
(+1)+(x)+3(-2) = 0
x = +5
And the oxidation number of N in is calculated as:
(+1)+(x)+2(-2) = 0
x = +3
From the oxidation number method, we conclude that the oxidation number reduced this means itself get reduced to
and it can act as an oxidizing agent.
act as a reducing agent.
The oxidation number of O in is calculated as:
(+1)+(+5)+3(x) = 0
x = -2
The oxidation number of O in is Zero (o).
Now, we conclude that the oxidation number increases this means itself get oxidized to
and it can act as reducing agent.