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Fudgin [204]
3 years ago
10

When describing metallic bonding, scientists note that the metal ions seem to be floating in a sea of electrons. This arrangemen

t contributes to the physical property of in metals.
Chemistry
1 answer:
horrorfan [7]3 years ago
3 0

True

Explanation:

Metallic bonds joins atoms of metals and alloys together. The formation of this bond type is favored by large atomic radius, low ionization energy and a large number of electrons in the valence shell.

  • This bond type is actually an attraction between the positive nuclei of all closely packed atoms in the lattice and the electron cloud jointly formed by all atoms.
  • Some of the physical properties of metals such as malleability, ductility, electrical and thermal conductivity, luster, high melting point e.t.c stems from this.

Learn more:

Bond types brainly.com/question/6071838

#learnwithBrainly

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For each of the following, use the periodic table to determine the number of valence electrons in an atom of the element.
Kipish [7]

Explanation:

Ne 8. S 6. Mg 2. Sn 4. C 4. Al 3. Te 6. Cs 1. Bi 5. Br 7. Ga 3. P 5.

5 0
3 years ago
2. The ions in an ionic compound separate from each other when
kkurt [141]

Answer:

A. when dissolved in water

Explanation:

Water is an extremely polar molecule, meaning it has a positive end a negative end. When an ionic compound is dissolved, the positive pole of water will be attracted to the negative ion and attach itself to it. The same goes for the positive ions. That's how water breaks down ionic compounds

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3 years ago
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Both protons and neutrons (and their anti-particles) froze out:
VladimirAG [237]
I think Both protons and neutrons (and their anti-particles) froze out at 1013 K, about 0.0001 seconds after the Big Bang. Protons and neutrons are sub atomic particles of an atom that are found in the nucleus of an atom. Proton is the positively charge particle while the neutron has no charge. The proton positive charge accounts for the positive nuclear charge. 
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4 years ago
The absorbance of a cationic iron(II) sample solution was measured in a spectrophotometer, but the instrument returned an error
JulijaS [17]

Answer:

1.35\times 10^{-4} M was the concentration of the original solution.

Explanation:

M_1V_1=M_2V_2  (Dilution)

where,

M_1\text{ and }V_1 are molarity and volume of non diluted sample.

M_2\text{ and }V_2 are molarity and volume of diluted sample.

M_1=?

V_1=100.0 \mu L=0.1 mL

(1μL=0.001  mL)

M_2=6.41\times 10^{-6} M

V_2=2.00 mL + 100.0 \mu L=2.00 mL+0.1 mL=2.1 mL

Substituting all values :

M_1\times 0.1 mL=6.41\times 10^{-6} M\times 2.1 mL

M_1=\frac{6.41\times 10^{-6} M\times 2.1 mL}{0.1 mL}=1.35\times 10^{-4} M

1.35\times 10^{-4} M was the concentration of the original solution.

5 0
3 years ago
Fill in the flowing information for the element uranium
UkoKoshka [18]

Answer:

Period: 7

Family: actinides

Group: Actinide

Explanation:

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3 years ago
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