How does size influence the appearance of a star? Give an example in your response

Chemistry

2 answers:

Maurinko [17]3 years ago

7 0

Makes it seem bigger and brighter

In-s [12.5K]3 years ago

3 0

When the size of a star increases, the brighter it gets.

The color of the star is determined by the temperature.

If the temperature of the star is lower, that means the star is an orange/red color.

If the star's temperature is higher, that means the star is an blue/white color.

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If a mineral with a density of 6 g/cm3 is broken into 3, what is the density of each new piece?

mamaluj [8]

Answer:

If a mineral with a density of 6 g/cm3 is broken into 3, the density of each new piece is 6 $\frac{g}{cm^{3} }$

Explanation:

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. In other words, density is the property that matter, whether solid, liquid or gas, has to compress into a given space, the amount of mass per unit volume.

As density is a physical property of matter that is defined as the ratio of an object's mass to its volume, each material or substance has its own density regardless of its size because the ratio between mass and volume is the same.

If a mineral with a density of 6 g/cm3 is broken into 3, the density of each new piece is 6 $\frac{g}{cm^{3} }$

6 0

3 years ago

How many atoms in 4.5 moles of carbon (C)?

vova2212 [387]

Answer:

34 atoms

Explanation:

3 0

3 years ago

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Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu

stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = $e^{-2.54738}$