The group is might be labeled as VIIB or VIIA.
Answer:
Alumminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+H2SO4-->Al2(SO4)+6H2O.
Explanation:
plz mark as brainlist
<u>Answer:</u> The concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M
<u>Explanation:</u>
We are given:
Molarity of bromoacetic acid = 0.100 M
Percent of ionization = 13.2 %
The chemical equation for the ionization of bromoacetic acid follows:

1 mole of bromoacetic acid produces 1 mole of bromoacetate ion and 1 mole of hydrogen ion
Molarity of hydrogen ion = 13.2 % of 0.100 = 
Molarity of bromoacetate ion = molarity of hydrogen ion = 0.0132 M
Molarity of bromoacetic acid = Molarity of solution - Molarity of ionized substance
Molarity of bromoacetic acid = 0.100 - 0.0132 = 0.0868 M
Hence, the concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M
We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
<h3>
Chemical Reaction</h3>
Question Parameters:
An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as

where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore

Morality=8.83/1.115
Morality=7.91mol/l
For more information on Chemical Reactionvisit
brainly.com/question/11231920