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Goshia [24]
3 years ago
7

What is the frequency of a particular type of electromagnetic

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

f = 0.6× 10¹⁶ Hz

Explanation:

Given data:

Wavelength of radiation = 5.00 × 10⁻⁸ m

Frequency of radiation = ?

Solution:

Formula:

Speed of light = wavelength × frequency

speed of light = 3 × 10⁸m/s

Now we will put he values in formula.

3 × 10⁸m/s = 5.00 × 10⁻⁸ m ×  f

f = 3 × 10⁸m/s / 5.00 × 10⁻⁸ m

f = 0.6× 10¹⁶ s⁻¹

s⁻¹ = Hz

f = 0.6× 10¹⁶ Hz

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Which group of the periodic table contains two elements that are gases at stp?
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The group is might be labeled as VIIB or VIIA.
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Write the word and balanced chemical equations for the reaction between:
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2 years ago
A 0.100 M solution of bromoacetic acid (BrCH2COOH) is 13.2% ionized. Calculate [H+]? Calculate BrCH2COO^ - ? Calculate BrCH2COOH
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<u>Answer:</u> The concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M

<u>Explanation:</u>

We are given:

Molarity of bromoacetic acid = 0.100 M

Percent of ionization = 13.2 %

The chemical equation for the ionization of bromoacetic acid follows:

BrCH_2COOH\rightarrow BrCH_2COO^-+H^+

1 mole of bromoacetic acid produces 1 mole of bromoacetate ion and 1 mole of hydrogen ion

Molarity of hydrogen ion = 13.2 % of 0.100 = \frac{13.2}{100}\times 0.100=0.0132M

Molarity of bromoacetate ion = molarity of hydrogen ion = 0.0132 M

Molarity of bromoacetic acid = Molarity of solution - Molarity of ionized substance

Molarity of bromoacetic acid = 0.100 - 0.0132 = 0.0868 M

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8 0
3 years ago
An aqueous solution of methanol (MM = 32.04 g/mol) has a molality of 8.83 m and a density of 1.15 g/mL. What is the molarity of
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We have that the  the molarity of methanol in the solution is mathematically given as

Morality=7.91mol/l

<h3>Chemical Reaction</h3>

Question Parameters:

An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)

A molality of 8.83 m and a density of 1.15 g/mL.

Generally the equation for the   is mathematically given as

Morality=\frac{moles of solute }{mass of the solvent}

where

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Mass of solution=1289.9

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Therefore

Morality=\frac{moles of solute }{mass of the solvent}

Morality=8.83/1.115

Morality=7.91mol/l

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7 0
2 years ago
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