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4 years ago

What is a materials ability to be dissolved in a solvent

1 answer:

5 0

Answer: Solubility

Solubility is the ability to be dissolved. Saturation is when the concentration is too high(more than solubility) that when you add another material it won't dissolve. Solute is the material that dissolved. Solvent is the material that used for dissolving

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Water is more elastic than air. Why?

zhannawk [14.2K]

<span>Air is more compressible than water. Further, volume elasticity is reciprocal of compressibility. Therefore, water is more elastic than air.</span>

6 0

4 years ago

Nine tree lights are connected inparallel across 120-V potential difference. The cord to the wall socket carries a current of 0.

jok3333 [9.3K]

Answer:

a)3000ohm

b)4.44mA

Explanation:

a) we were given a Nine tree lights connected inparallel across 120-V potential difference, since the resistor are in parallel we use the expresion below

1/R(total)= 1/R₁ + 1/R₂ + 1/R₃ + 1/R₃ +.... 1/R₉

But according to ohm'law which can be expressed below

V=IR

R=V/I

R(total)= 120/0.36

= 333.33ohm

1/R(total)= 1/R₁ + 1/R₂ + 1/R₃ + 1/R₃ +.... 1/R₉

R₁=R₂ =R₃ =R₄= R₅=R₆=R₇=R₈=R₉

1/R(total)=9/R

1/333.33= 9/R

R= 3000ohm

Therefore, the resistance is 3000ohm

b)the bulbs were connected in series here, then for series connection we use below expression

R₁=R₂ =R₃ =R₄= R₅=R₆=R₇=R₈=R₉

R(total)=9R

= 9*3000

=27000ohm

I=VR

I=V/R

I= 120/27000

= 4.44*10⁻³A

4.44mA

Therefore, the current is 4.4mA

7 0

4 years ago

You are traveling at 14 m/s for 20 seconds. What is your displacement?

enyata [817]

Velocity = 14 m/s

Time = 20 s

Displacement = Velocity×Time = (14×20) m = 280 m

The displacement is 280 m towards the direction of motion.

5 0

3 years ago

Read 2 more answers

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?

SpyIntel [72]

Answer:

U= $0.112 x10^{-6}$ J

u= 0.708 $\frac{J}{m^{3} }$

Explanation:

diameter= 2 cm

$r= 1 cm * \frac{1m}{100cm} = 0.01 m$

distance= 0.5 mm

$d= 0.5 mm * \frac{1m}{1000m}= 0.5 x10^{-3}$

Area A= $\pi *r^{2}= 0.314x10^{-3} m^{2}$

Volume v= $A*d = 0.314 x10^{-3}m^{2}*0.5x10^{-3} m =0.157x10^{-6} m^{3}$

$v= 0.157 x10^{-6} m^{3}$

Constant vacuum permittivity

$E_{o}= 8.85x10^{-12}$

a).

$C= \frac{A*E_{o} }{d} = \frac{0.314x10^{-3} *8.85x10^{-12} }{0.5x10^{-3} } \\C= 5.56 x10^{-12}$ F

$U= \frac{1}{2} *C *V^{2}\\ U=\frac{1}{2} * 5.56x10^{-12}*(200)^{2} \\U=0.112 x^{-6} J\\$

b).

$u=\frac{U}{v}$

$u=\frac{0.112 x10^{-6}J}{0.157x10^{-6}m^{3} } \\u=0.708 \frac{J}{m^{3} }$

5 0

4 years ago

A 2000 kg car moves down a level highway under the actions of two forces. one is a 1060 n forward force exerted on the drive whe

kipiarov [429]

Refer to the diagram shown below.

The net force acting on the vehicle is
F - R = 1060 -1010 = 50 N

The distance traveled is 21 m. Because the force is constant, the work done is
W = (50 N)*(21 m) = 1050 J

Assume that energy is not dissipated by air resistance or otherwise.
Conservation of energy requires that W = KE, where KE is the kinetic energy of the vehicle.
The KE is
KE = (1/2)*(2000 kg)*(v m/s)² = 1000v² J

Equate KE and W to obtain
1000v² = 1050
v² = 1.05
v = 1.025 m/s

Answer: 1.025 m/s

3 0

4 years ago