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2 years ago

PLS HELP IM SOO CONFUSED!

Physics

2 answers:

Feliz [49]2 years ago

7 0

False.

As temperature increases the more the electrons begin to vibrate more, as it decreases they vibrate less.

Troyanec [42]2 years ago

5 0

Answer:

false

Explanation:

the motion creates current and heat at the same time

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An ice skater glides for two meters across ice is work done or no work done

garik1379 [7]

Work is done. work=forcexdisplacement. the ice skater glides 2 meters (displacement), so yes.

5 0

2 years ago

Hi, Please help me with the 2 questions, will mark and 5 stars and THANKS

Anit [1.1K]

Both answers are going to be C

7 0

2 years ago

Read 2 more answers

(a) Two ions with masses of 4.39×10^−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic fiel

sammy [17]

Answer:

Part a)

$R_1 = 0.072 m$

Part b)

$R_2 = 0.036 m$

Part c)

d = 0.072 m

Explanation:

Part a)

As we know that the radius of the charge particle in constant magnetic field is given by

$R = \frac{mv}{qB}$

now for single ionized we have

$R_1 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(1.6 \times 10^{-19})(0.301)}$

$R_1 = 0.072 m$

Part b)

Similarly for doubly ionized ion we will have the same equation

$R = \frac{mv}{qB}$

$R_2 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(3.2 \times 10^{-19})(0.301)}$

$R_2 = 0.036 m$

Part c)

The distance between the two particles are half of the loop will be given as

$d = 2(R_1 - R_2)$

$d = 2(0.072 - 0.036)$

$d = 0.072 m$

6 0

2 years ago

The work done by the brakes during braking is equal to

kow [346]

Answer:

The amount of pressure delivered to them

Explanation:

6 0

1 year ago

(a) Consider a fusion generator built to create 3.00 GW of power. Determine the rate of fuel burning in grams per hour if the DT

Stels [109]

The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 × $10^1^3$ J/g per hour

<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>

D + T → He + n
The D-T fusion reaction results in a Helium (He) and neutron (n)

E = 17.59 MeV

Mass = 2.014u + 3.016u

= 5.030u

Energy per Kg = (17.59× $10^6$ ×1.6× $10^-^1^9$ ) ÷ ( 5.030×1.66× $10^-^2^7$ )

= 3.37× $10^1^4$ J/Kg

= 3.0× $10^9$ J/g

Rate of fuel burning in grams per hour = 3.0× $10^9$ × 3600

= 3.6×3.0× $10^1^2$

= 1.08 × $10^1^3$ J/g per hour

To learn more about fusion reactor and energy production, refer

brainly.com/question/13399644

#SPJ4

4 0

1 year ago