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fomenos
3 years ago
5

Two charged concentric spherical shells have radii 8.83 cm and 15.4 cm. The charge on the inner shell is 5.03 × 10⁻⁸ C and that

on the outer shell is 2.77 × 10⁻⁸ C. Find the electric field (a) at r = 11.1 cm and (b) at r = 36.1 cm.
Physics
1 answer:
REY [17]3 years ago
3 0

Answer:

a. E(r) = 3.67 x 10⁴ N/C

b. E(r) = 5.38 x 10⁴ N/C

Explanation:

r1 = 8.83 cm

r2 = 15.4 cm

Charge on the inner shell = 5.03 x 10^-⁸ C

Charge on the outer shell = 2.77 x 10^-⁸ C

a)   To find the electric field at r = 11.1 cm,

r₁ = 8.83 cm < r = 11.1 cm < r₂ = 15.4 cm

E(r) = <u>1              </u> <u>q₁    </u>

          4\pi∈₀        r₂  

E(r) = <u>( 8.99 x 10⁹ N.m²/C² )  ( 5.03 x 10⁻⁸)</u>

                                 (0.111m)²

E(r) = 3.67 x 10⁴ N/C

b)   To find the electric field at r = 36.1 cm

since r₁  < r₂ < r = 36.1 cm

E(r) = <u>1              </u> <u>q₁  ₊  q₂   </u>

          4\pi∈₀           r₂  

E(r) = <u>( 8.99 x 10⁹ N.m²/C² )  ( 5.03 + 2.77 )(1 x 10⁻⁸)</u>

                                             (0.361m)²

E(r) = 5.38 x 10⁴ N/C

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A research submarine has a 20-cm-diameter window that is 9.0 cm thick. The manufacturer says the window can withstand forces up
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Put the value into the formula

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Angelina_Jolie [31]

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2 years ago
A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration?
Scrat [10]

Answer:

{ \boxed{ \bold{ \sf{Acceleration \: ( \: a) = 8 \: m/ {s \: }^{2} }}}}

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

♨ Question :

  • A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration ?

♨ \underbrace{ \sf{Required \: Answer : }}

☄ Given :

  • Initial velocity ( u ) = 0
  • Final velocity ( v ) = 60.0 m/s
  • Time ( t ) = 7.50 s

☄ To find :

  • Acceleration ( a )

✒ We know ,

\boxed{ \underline{ \bold{ \sf{Acceleration \: ( \: a) =  \frac{Final velocity ( v )  - Initial velocity ( u)}{t} }}}}

Substitute the values and solve for a.

➛ \sf{a =  \frac{60.0 - 0}{7.50}}

➛ \sf{a =  \frac{60.0}{7.50}}

➛ \boxed{ \boxed{ \sf{a = 8 \: m/ {s \: }^{2} }}}

---------------------------------------------------------------

✑ Additional Info :

  • When a certain object comes in motion from rest , in the case , initial velocity ( u ) = 0
  • When a moving object comes in rest , in the case , final velocity ( v ) = 0
  • If the object is moving with uniform velocity , in the case , u = v.
  • If any object is thrown vertically upwards in the case , a = -g
  • When an object is falling from certain height , in the case , final velocity at maximum height ( v ) = 0.

Hope I helped!

Have a wonderful time ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

4 0
2 years ago
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