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3 years ago

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The reaction between aluminium powder and iron(III) oxide is used in the rail industry. a. i) write a word equation and a balanc

ed symbol equation for the reaction that takes place. ii) what do you call this type of reaction?

1 answer:

Phantasy [73]3 years ago

5 0

2Al + Fe2O3 ——-> Al2O3 + 2Fe

This is a single displacement reaction

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PLEASE HELPP!! What is the heat of reaction for the process NH4CI (s) ----> NH3 (g)+HCI (g)

vladimir2022 [97]

Answer:

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Explanation:

What is the heat of reaction for the process NH4CI (s) ----> NH3 (g)+HCI (g)

The reaction taking place is a gas-phase acid-base reaction (both HCl and NH3 are volatile), that produces particulate NH4Cl as the sole product: HCl(g) + NH3(g) → NH4Cl(s). 1.

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Answer:The natural world contains about 8.7 million species, according to a new estimate described by scientists as the most accurate ever. But the vast majority have not been identified - and cataloguing them all could take more than 1,000 years.

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3 years ago

6. The concentration of a solution is : a)The amount of solvent needed to fully dissolve a solute b)The measurement of how large

Maurinko [17]

Answer:

Option c) The measurement of how much solute can be dissolved in a liter of solvent.

Explanation:

The concentration of a solution can be defined as the amount of solute in 1 litre of the solvent i.e how much of the solute that can dissolve in a litre of the solvent. Mathematically, it can be written as:

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3 years ago

How many grams of H2 can be formed from 54.6 grams of NH3 in the following reaction? 2NH3 (g) --> 3H2 (g) + N2 (g)

Strike441 [17]

Answer:

9.64g

Explanation:

The balanced equation for the reaction is given below:

2NH3 (g) —> 3H2 (g) + N2 (g)

Next, we need to calculate the mass NH3 that decomposed and the mass of H2 produced from the balanced equation. This is illustrated below:

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 that decomposed from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 produced from the balanced equation = 3 x 2 = 6g.

Now, we can obtain the mass of H2 formed from 54.6g of NH3 as follow:

From the balanced equation above,

34g of NH3 decomposed to produce 6g of H2.

Therefore, 54.6g of NH3 will decompose to produce = (54.6x6)/34 = 9.64g of H2

Therefore, 9.64g of H2 can be obtained from 54.6g of NH3.

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3 years ago

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arlik [135]

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