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PSYCHO15rus [73]
3 years ago
7

What is the slope of the line represented by the equation y = y equals 4 Over 5

Mathematics
2 answers:
Kruka [31]3 years ago
6 0
<h2>Answer:</h2>

The slope of the given line is:

                        \dfrac{4}{5}

<h2>Step-by-step explanation:</h2>

We know that if a line is represented in the slope intercept form i.e.

             y=mx+c

then m represents the slope of the line and c represents the y-intercept of the line.

Here we are given a equation of a line as follows:

                y=\dfrac{4}{5}x-3

i.e. on comparing the equation with  the slope-intercept form of the line we have the slope  of the line is:

             m=\dfrac{4}{5}

OLEGan [10]3 years ago
4 0

\bf y= \stackrel{\stackrel{m}{\downarrow }}{\cfrac{4}{5}}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

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Mkey [24]

Answer:

a. The mean refractory period= 1.85 and the standard error = 0.06455

b.  90% confidence interval for the mean absolute refractory period for all mice when subjected to the same treatment = 1.6981, 2.0019

c. Yes, the data give good evidence to support this theory

Step-by-step explanation:

a.  The table below shows the calculations:

                 X                (X-mean)^2

                1.7             0.0225

                1.8                 0.0025

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The standard error, se= \frac{s}{\sqrt{n}}=\frac{0.1291}{2} = 0.06455

b. Degree of freedom: df = n-1 = 3

Critical value of t for 90% confidence interval is: 2.3534

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c. The Hypotheses are:

H_{0}:\mu=1.3,H_{1}:\mu>1.3

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Answer:

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Step-by-step explanation:

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Answer:

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