Answer:
16/33
Step-by-step explanation:
12C4(total possible outcomes)=495
Since there are 6 married couples there must be 6*[2C2×10C2]=270
must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255
the no of groupings with no married couples 495-255 =240
probability=no of favourable outcomes /no of possible outcome
probability=240/495= 16/33
Answer:
1) 12
2) c=-25
3) x = -16 2/3
Step-by-step explanation:
1) ..........................
- 6*(4-10+8) =
- 6*(- 6+8) =
- 6*2=
- 12
2) ..........................
- 34 + 2c = -16
- 2c = - 16 -34
- 2c = -50
- c = -50/2
- c=-25
3) ..........................
- 40 = -3x - 10
- 40+ 10 = -3x
- -3x = 50
- x = 50/-3
- x=-16 2/3
Answer:
1. A. AC=3IN
2. D AND C
Step-by-step explanation:
Answer:
-5,-8,-11,-14,-17
Step-by-step explanation:
-3n -2
n=1 -3(1) -2 = -3-2 = -5
n=2 -3(2) -2 = -6-2 = -8
n=3 -3(3) -2 = -9-2 = -11
n=4 -3(4) -2 = -12-2 = -14
n=5 -3(5) -2 = -15-2 = -17
