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seropon [69]
3 years ago
14

What if the earth was flat

Physics
2 answers:
Zinaida [17]3 years ago
8 0
If the Earth were flat, then ...

-- the sun would never rise;

-- the sun would never set;

-- the sun would look larger and smaller at different times of day;

-- you would be able to see Mt. McKinley, Mt. Everest, Mt. Pinatubo,
and Mt. Kilimanjaro, all from your front yard or your bedroom window;

-- in fact, when the air is clear, you would be able to see the Sears Tower
(here in Chicago) from your front yard or your bedroom window;

-- the shadow of the Earth, falling across the moon, would be some times
circular, some times elliptical, and some times straight, instead of always
circular every time;

-- when you're on the beach, watching a ship sail away from you,
it would just get smaller and smaller and smaller as it got farther
and farther and farther from you; you would never see any of it
disappear, instead of seeing it disappear from the bottom up
the way it actually does.

Lots and lots of other things would also look different and happen
different from the way they actually do look and happen now.
mina [271]3 years ago
5 0
Then everyone would fall off the surface
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When motion IS changing directions, acceleration is the rate at which ________changes, but when motion is NOT changing direction
iVinArrow [24]
The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>When motion IS changing directions, acceleration is the rate at which velocity changes, but when motion is NOT changing direction, acceleration may be expressed as the rate at which speed changes.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
An electrical heater is used to supply 245.0 J of energy to a 15.0 g sample of aluminum, originally at 310.0 K. Determine the fi
Softa [21]

Answer:

T_f=328.1 K

Explanation:

To determine the final temperature of the sample, we use the specific heat formular as follows:

Q=mCp(T_f-T_0)\\T_f=\frac{Q}{mCp} +T_{0}\\mol Al= \frac{15g}{26.98gmol^{-1}}=0.555 mol\\T_f=\frac{245.0J}{0.555mol\times24.35Jmol^{-1}K^{-1}} +310.0K\\T_f=328.1 K

Finally, the temperature of the aluminium sample has raised 18 K.

8 0
4 years ago
The Space Shuttle does not directly inject into its prescribed mission orbit. Rather, themain engine shutdown occurs at the apog
iris [78.8K]

Answer:

(a) burnout speed at apogee in the external tank disposal orbit=7.82 km/sec

(b) ΔV required for the OMS-1 =0.066 km/sec

(c) ΔV required for the OMS-2 =0.045 km/sec

(d) This part of the question is explained in detailed way in the attached file.

Explanation:

Detailed explanation of all the parts of the question are given in attached files.

8 0
3 years ago
According to the reading, which of the following is NOT an obstacle to using big data for analysis and decision making? O Poor r
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Answer:

B .Limited types of data Insufficient data

Explanation:

To analyse and making decision from big data we have following thing

- Sufficient data

- data analyst

- Accurate data

- data Privacy

- data storage

So, limited data or data that cannot be copied is not and obstacle in data handling. hence option B Limited types of data Insufficient data is correct.

3 0
4 years ago
two vehicles have a head on collision. one vehicle has a mass of 3000 kg and moves at 25 m/s while the second vehicle has a mass
emmasim [6.3K]

Answer:

The speed of the combined vehicles is 6.82m/s

Explanation:

Using the law of conservation of momentum which stayed that the sum of momentum of bodies before collision is equal to their sum of momentum after collision. After collision, both object moves with the same velocity.

Momentum = mass×velocity

Before collision:

Momentum of vehicle or mass 3000kg moving with velocity 25m/s

= 3000×25

= 75000kgm/s

Pa = 75000kgm/s

Momentum of vehicle with mass 2500kg moving with velocity of -15m/s

= 2500×-15

= -37500kgm/s

After collision:

Momentum = (3000+2500)V

Where v is their common velocity

Momentum after collision = 5500V

Based on the law:

75000+(-37500) = 5500V

75000-37500 = 5500V

37500 = 5500V

V = 37500/5500

V = 6.82m/s

7 0
3 years ago
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