Question

A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump. Assuming normal atmospheric pressure outside the can, find the total force (in lb) on one of the 5-by-19 in. sides. (Enter the magnitude.)

Answer 1

Answer:

The force is  $F = 1397 lb$

Explanation:

From the question we are told that

    The length of the box is  $l = 19 \ in$

    The width of the box is  $w = 5 \ in$

     The height is  $h = 4\ in$

The pressure experience on one of the sides is mathematically represented as

     $p = \frac{F}{A}$

Where A is the area of the box which is mathematically evaluated as

    $A = l * w$

substituting values

     $A = 5 *19$

      $A = 95 \ in^2$

This pressure is equivalent to the atmospheric pressure which has a constant value of  $p = 14.7 pi$

This implies that

        $14.7 = \frac{F}{95}$

=>   $F = 14.7 *95$

=>    $F = 1397 lb$