Answer:
"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."
Step-by-step explanation:
A Type I error happens when a true null hypothesis is rejected.
In this case, as the claim that want to be tested is that the average wind speed is significantly higher than 15 mph, the null hypothesis has to state the opposite: the average wind speed is equal or less than 15 mph.
Then, with this null hypothesis, the Type I error implies a rejection of the hypothesis that the average wind speed is equal or less than 15 mph. This is equivalent to say that there is evidence that the average speed is significantly higher than 15 mph.
"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."
4g and 6b and that's a total of 10 in all so you know it will be 1/2 if its going to be two out of two
Answer:
![h = 15.163\ meters](https://tex.z-dn.net/?f=h%20%3D%2015.163%5C%20meters)
Step-by-step explanation:
(Assuming the correct angles are 30° and 45°)
We can use the tangent relation of the angle of elevation to find two equations, then we can use these equations to find the height of the pole.
Let's call the initial distance of the boy to the pole 'x'.
Then, with an angle of elevation of 30°, the opposite side to this angle is the height of the pole (let's call this 'h') minus the height of the boy, and the adjacent side to the angle is the distance x:
![tan(30) = (h - 1.5) / x](https://tex.z-dn.net/?f=tan%2830%29%20%3D%20%28h%20-%201.5%29%20%2F%20x)
Then, with an angle of elevation of 45°, the opposite side to this angle is still the height of the pole minus the height of the boy, and the adjacent side to the angle is the distance x minus 10:
![tan(45) = (h - 1.5) / (x - 10)](https://tex.z-dn.net/?f=tan%2845%29%20%3D%20%28h%20-%201.5%29%20%2F%20%28x%20-%2010%29)
So rewriting both equations using the tangents values, we have that:
![0.5774 = (h - 1.5) / x](https://tex.z-dn.net/?f=0.5774%20%3D%20%28h%20-%201.5%29%20%2F%20x)
![1 = (h - 1.5) / (x - 10) \rightarrow (h - 1.5) = (x - 10)](https://tex.z-dn.net/?f=1%20%3D%20%28h%20-%201.5%29%20%2F%20%28x%20-%2010%29%20%5Crightarrow%20%28h%20-%201.5%29%20%3D%20%28x%20-%2010%29)
From the first equation, we have that:
![x = (h - 1.5) / 0.5774](https://tex.z-dn.net/?f=x%20%3D%20%28h%20-%201.5%29%20%2F%200.5774)
Using this value of x in the second equation, we have that:
![h - 1.5 = \frac{ (h - 1.5) }{0.5774} - 10](https://tex.z-dn.net/?f=h%20-%201.5%20%3D%20%20%5Cfrac%7B%20%28h%20-%201.5%29%20%7D%7B0.5774%7D%20-%2010)
![h + 8.5 = \frac{ (h - 1.5) }{0.5774}](https://tex.z-dn.net/?f=h%20%2B%208.5%20%3D%20%20%5Cfrac%7B%20%28h%20-%201.5%29%20%7D%7B0.5774%7D)
![0.5774h + 4.9079 = h - 1.5](https://tex.z-dn.net/?f=0.5774h%20%2B%204.9079%20%3D%20h%20-%201.5)
![0.4226h = 6.4079](https://tex.z-dn.net/?f=0.4226h%20%3D%206.4079)
![h = 15.163\ meters](https://tex.z-dn.net/?f=h%20%3D%2015.163%5C%20meters)