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daser333 [38]
3 years ago
15

If your heart beats 65 times in one minute, how many times does it beat in a day?

Mathematics
1 answer:
blagie [28]3 years ago
6 0

Answer:

It beats 93,600 times a day.

Step-by-step explanation:

There are 1,440 minutes in a day. So the equation would look like this: 65 x 1,440 = 93,600


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Solve the following:<br> -5² + 10²<br> (2 × (-5) × 3) + 3³<br> Give your answer in simplest form.
notsponge [240]
Problem 1: -5^2 + 10^2
Work:
-5^2 + 10^2—> (-5 x -5) + (10 x 10) —> 25 + 100 = 125
Answer:
125

Problem 2: (2 x (-5) x 3) + 3^3
Work:
(2 x (-5) x 3) + 3^3 > (-25 x 3) + 3^3 —> -75 + 3^3 —> -75 + 27 —> 48
Answer:
48
5 0
1 year ago
Use Long Division to find the answer. Please show all steps!
ValentinkaMS [17]

Answer:

The answer to your question is 2x² + 3x +  Remainder (17x - 7)/ ( 2x⁴  +  3x³  - 4x²  + 5x - 7)

Step-by-step explanation:

                             2x² + 3x

             x² - 4     2x⁴  +  3x³  - 4x²  + 5x - 7

                          -2x⁴              + 4x²

                            0      + 3x³   + 0    + 5x

                                     - 3x³             +12x

                                        0                +17x - 7

Quotient = 2x² + 3x

Remainder = 17x - 7

Solution  = 2x² + 3x + (17x - 7)/ ( 2x⁴  +  3x³  - 4x²  + 5x - 7)

Process

1.- Divide the first term of the divident by the first term of the divisor and place the result above the first term of the divident.

2.- Multiply the result of the division (2x²) by the first term of the divisor and change the sign of the result.

3.- Multiply the result (2x²) by the second term of the divisor and place the result below the like term.

4.- Add the results.

5.- Continue with this process until the remainder be lower than the divisor.

5 0
3 years ago
if an explosive shell can travel 500 yards in 1.5 seconds, a shell bursts with a 25 yard diameter of damage and it takes 3 secon
zzz [600]
an\ explosive\ shell\ can\ travel\ 500\ yards\ in\ 1.5\ seconds\ \ \ \rightarrow\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \rightarrow\ \ \ \  1000\ yards\ in\ 3\ seconds\\\\diameter = 25\ yards\ \ \ \ \ \rightarrow\ \ \ \ radius=12.5\ yards\\\\1000+12.5=1012.5\ [yards]\\\\Answer:\\ The\ farthest\ away\ a\ target\ could\ be\ hit\ with\  a\ shell\ is\ 1012.5\ yards
4 0
3 years ago
A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected. What is the probability
leonid [27]

Answer: 0.9544

Step-by-step explanation:

As per given have ,

Population mean : \mu=200

Standard deviation : \sigma=50

Sample size : n= 100

We assume that the population is normally distributed.

Let \overline{x} be the sample mean.

Now , the probability that the sample mean will be within ±10 of the population mean will be :-

P(200-10

P(\dfrac{190-200}{\dfrac{50}{\sqrt{100}}}

=P(\dfrac{-10}{\dfrac{50}{10}}

=P(\dfrac{-10}{5}

Hence, the required probability is 0.9544.

7 0
3 years ago
Pythagorean theorem 19^2 + 21^2=x^2
satela [25.4K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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