Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20
(x - a)(x - b) = 0
(x - (-2))(x - (-10)) = 0
(x + 2)(x + 10) = 0
x^2 + 10x + 2x + 20 = 0
x^2 + 12x + 20 = 0
-h = 12
h = -12
4k = 20
k = 5
If <span>y = -x + 7, and (-1,y) is on the graph, then the following is true: y=-(-1) + 7, or y=8.
Thus, y = a0 = 8.</span>
The first and the second one are true statements.
Required algebraic expression is 3/z
